Parametric radius of a circle
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Hey everyone!
Ive been trying to solve "the envelope problem" i uploaded a few days ago and ive made huge progress. However im now stuck on some silly little thing. I need to find the parametric equation for circles radius (later many circles will be drawn with that).
My code so far is :
syms a b p x y L
F = [p/2,0];
xpara = [x sqrt(2*p*x)];
eqn1 = a*F(1,1)+b == 0;
eqn2 = a*x+b == xpara(1,2);
eqns = [eqn1 eqn2];
%L - lambda.
eqns = [a*F(1,1)+b == 0, subs(a*x+b,x,L) == subs(xpara(1,2),x,L)];
S=solve(eqns,[a b],'ReturnConditions',true);
S.a;
S.b;
sirge =simplify(S.a*x+S.b);
loikepunktx = solve(sirge==-xpara(1,2),x,'ReturnConditions',true);
%sirge is a line equation
loikepunktx.x=loikepunktx.x(2,1);
loikepunktx.x;
sirge1 = simplify(S.a * loikepunktx.x + S.b);
sirge1;
LP = [loikepunktx.x, sirge1];
%Center = KP
KP = subs(simplify((xpara + LP)/2),x,L);
%ok so far
xpara;
KP;
In wolframalpha the solution would be
pR = Simplify[(xpara - KP) . (xpara - KP)] /. x -> \[Lambda]
and it gives the answer :

In MatLab however, im always getting a dot (i.e (x,y)) not the formula. Matlab doesnt simplify it like wolfram but the answer should be similar/ simplifiable to that form.
Probably going to be asking a few more questions while trying to progress but i am close to the end :)
Edit: i just did it the easy way:
R = subs(sqrt((xpara(1,1)-KP(1,1))^2+(xpara(1,2)-KP(1,2))^2),x,L)
But it doesnt give the same answers as in wolfram. The wolframalpha answer is squared of what matlab gives me. I dont know whether my WA has a mistake in it or my matlab code.
3 comentarios
darova
el 27 de Mayo de 2021
MATLAB has weak symbolic toolbox. WHat about numerical approach?
Stefan Juhanson
el 28 de Mayo de 2021
Stefan Juhanson
el 28 de Mayo de 2021
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