finding only unique values

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Bernard
Bernard el 22 de Ag. de 2013
Suppose you have a column vector, the values are integers(in order) but some of them are repeated, e.g. it could be [1,1,1,1,2,3,3,4,5,5,5,5,5] I want to find the indices of unique values e.g. the index of 2 and 4 in the aforementioned example. the unique function in matlab returns on top of truly unique the first value of any nonunique value, so it would return the index of the first 1, the first 3 and first 5 but I don't want those

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the cyclist
the cyclist el 22 de Ag. de 2013
Editada: the cyclist el 22 de Ag. de 2013
Maybe call these the "singleton" values. Here's one way:
x = [1,1,1,1,2,3,3,4,5,5,5,5,5];
unique_x = unique(x);
count_x = hist(x,unique_x);
singleton_x = unique_x(count_x==1)
  1 comentario
Bernard
Bernard el 22 de Ag. de 2013
brilliant this saved me time thanks

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Más respuestas (2)

David Sanchez
David Sanchez el 22 de Ag. de 2013
a=[1,1,1,1,2,3,3,4,5,5,5,5,5];
x = unique(a)
y = histc(a,x)==1;
lonely_values = find ( y == 1 )
or:
lonely_values = find ( (histc(a,unique(a))==1) == 1 )
lonely_values =
2 4

Azzi Abdelmalek
Azzi Abdelmalek el 22 de Ag. de 2013
[ii,jj]=sort(x);
out=sort(jj(strfind(logical([1 diff(ii) 1]),[true,true])))

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