random number generation for known sum
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    harley
 el 27 de Ag. de 2013
  
    
    
    
    
    Comentada: Tejas
 el 14 de Jul. de 2020
            i what do generate some 15 random numbers that sum for each separate value of say, 60 , 70, 40, 65. How would i go abouts this?
sum = [60 70 40 65];
n=15;
b = [ ];
for i = 1:1:n,
a = randi([1,??]);
b = [b a];
end
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  Azzi Abdelmalek
      
      
 el 27 de Ag. de 2013
        n=60;
m=1:n;
a=m(sort(randperm(60,15)));
b=diff(a);
b(end+1)=60-sum(b)
sum(b)
13 comentarios
  Bruno Luong
      
      
 el 13 de Jul. de 2020
				
      Editada: Bruno Luong
      
      
 el 13 de Jul. de 2020
  
			The easiest way is perhaps using Roger FEX function, then do some sort of "integering" the float solution
sumatarget = 60
n = 15;
ub = 7;
x = floor([0; cumsum(randfixedsum(n,1,sumatarget,0,ub))]); 
x(end) = sumatarget; % prevent floating point error
r = diff(x)
The distribution might be not perfectly uniform but possibly close enough and suitable for what ever you want to do with it.
  Tejas
 el 14 de Jul. de 2020
				Integering the solution from Roger's function works very well for me. I do not require the numbers to be perfectly uniform. Thanks!
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