An object with the biggest amount of scope in the Binary image
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Hello, I have a binary image with n white objects (not connected). How can I leave only the object with the biggest amount of scope in the picture I can do it by - bwareaopen, but in this way I have to know approximate size of an object. sorry for my english. thnx
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Image Analyst
el 13 de Sept. de 2013
Try this:
grayImage = imread('coins.png');
subplot(2,2,1);
imshow(grayImage);
binaryImage = grayImage > 100;
binaryImage = imfill(binaryImage, 'holes'); % Fill holes.
[labeledImage, numObjects] = bwlabel(binaryImage);
stats = regionprops(labeledImage,'Area');
allAreas = [stats.Area]
[~, indexOfLargest] = max(allAreas);
largestBlob = ismember(labeledImage, indexOfLargest)>0;
subplot(2,2,2);
imshow(largestBlob);
title('Largest');
keeperIndexes = 1:numObjects;
keeperIndexes(indexOfLargest) = [];
binaryImage2 = ismember(labeledImage, keeperIndexes)>0;
subplot(2,2,3);
imshow(binaryImage2);
title('All Except Largest');
Más respuestas (2)
Adam Filion
el 12 de Sept. de 2013
Editada: Adam Filion
el 12 de Sept. de 2013
If you have Image Processing Toolbox you can use the function regionprops. It comes out to something like this, where tm is the binary image.
cc = bwconncomp(tm);
stats = regionprops(cc,'Area');
A = [stats.Area];
[~,biggest] = max(A);
tm(labelmatrix(cc)~=biggest) = 0;
You can watch a recorded presentation that steps through a similar example here:
Sean de Wolski
el 17 de Sept. de 2013
Good timing, I just posted this function a few minutes ago!
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