Vectorization of for loop

1 visualización (últimos 30 días)
Safwana Razak
Safwana Razak el 15 de Jul. de 2021
Respondida: Jayant Gangwar el 15 de Jul. de 2021
B = randi(10x5);
x = randi(10x40);
y = randi(10x1);
% Modelfun = equation to fit
% I can do a for loop like this:
for i=1:10
[beta(i,:)]=nlinfit(x(i,:),y(i,:),modelfun,B)
end
Can I do vectorization? for example 10 fittings all at once, without using loops? or maybe using @cellfun or @arrayfun?
  1 comentario
KSSV
KSSV el 15 de Jul. de 2021
Editada: KSSV el 15 de Jul. de 2021
cellfun, arrayfun also uses loop inside...

Iniciar sesión para comentar.

Respuestas (1)

Jayant Gangwar
Jayant Gangwar el 15 de Jul. de 2021
It seems to me that you want to avoid the use of loops for finding all the rows of beta, You can do it by directly passing the complete x matrix and y vector to the nlinfit function, It will automatically save the answer in different rows of beta. An example of the same is given below-
S = load('reaction');
X = S.reactants; % 13x3 matrix
y = S.rate; % 13x1 vector
beta0 = S.beta;
[beta,R,J,CovB,MSE,ErrorModelInfo] = nlinfit(X,y,@hougen,beta0,'ErrorModel','combined');
beta
This is an example given in the documentation for nlinfit, for more information please take a look at the documentation for nlinfit - Nonlinear regression - MATLAB nlinfit (mathworks.com)

Categorías

Más información sobre Matrix Indexing en Help Center y File Exchange.

Productos


Versión

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by