Rounding using 'fix'... possibly a bug?

2 visualizaciones (últimos 30 días)
Brad
Brad el 14 de Oct. de 2013
Comentada: Brad el 15 de Oct. de 2013
Could someone tell me if this is a bug, or is there some logical reason 'fix' would round:
.3/.1 = 2
whereas
.4/.1 = 4
K>> fix(.3/.1)
ans =
2
K>> fix(.4/.1)
ans =
4
K>> fix(.7/.1)
ans =
6
K>> fix(.5/.1)
ans =
5
  1 comentario
Jan
Jan el 14 de Oct. de 2013
It is such surprising that the well known floating point effects appear for beginners usually for the value 0.3 . Usually it is:
find((0:0.1:1) == 0.3) % replies [] !!!

Iniciar sesión para comentar.

Respuesta aceptada

James Tursa
James Tursa el 14 de Oct. de 2013
To see what is going on you can examine the exact floating point values. Note that none of your original numbers except 0.5 can be represented in IEEE double format exactly:
>> num2strexact(.7)
ans =
0.6999999999999999555910790149937383830547332763671875
>> num2strexact(.5)
ans =
0.5
>> num2strexact(.4)
ans =
0.40000000000000002220446049250313080847263336181640625
>> num2strexact(.3)
ans =
0.299999999999999988897769753748434595763683319091796875
>> num2strexact(.1)
ans =
0.1000000000000000055511151231257827021181583404541015625
>> num2strexact(.7/.1)
ans =
6.99999999999999911182158029987476766109466552734375
>> num2strexact(.5/.1)
ans =
5
>> num2strexact(.4/.1)
ans =
4
>> num2strexact(.3/.1)
ans =
2.999999999999999555910790149937383830547332763671875
You can find num2strexact here:
  1 comentario
Brad
Brad el 15 de Oct. de 2013
Thank you James, much appreciated!

Iniciar sesión para comentar.

Más respuestas (1)

Image Analyst
Image Analyst el 14 de Oct. de 2013
Looks like another case explained by the FAQ.

Categorías

Más información sobre Coordinate Transformations and Trajectories en Help Center y File Exchange.

Productos

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by