interpolating row data in a matrix

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Natalie
Natalie el 15 de Oct. de 2013
Respondida: Natalie el 18 de Oct. de 2013
I have a large set of data that I need to linearly interpolate evenly by a factor of 22. The way that the data is organised means that the each row of data needs to be interpolated instead of each column, how do I make it so that rows of data are interpolated instead of columns?

Respuesta aceptada

Natalie
Natalie el 18 de Oct. de 2013
Sat down with someone and worked it out together:
num_rows = length(a); num_columns = 22;
b = zeros(num_rows,num_columns); c = zeros(num_rows,num_columns);
for i = 1:num_rows
count = a(i,13);
int_c(i,:) = (0:1/(num_columns - 1):1)*c(i,count);
int_b(i,:) = interp1(b(i,1:count), b(i,1:count), new_thick(i,:),'spline');
end
end

Más respuestas (2)

Walter Roberson
Walter Roberson el 15 de Oct. de 2013
newV = interp1(X, V.', newX) .';
  1 comentario
Natalie
Natalie el 16 de Oct. de 2013
Sorry, forgot to mention that there are a bunch of Nan values so this doesn't work

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Youssef  Khmou
Youssef Khmou el 15 de Oct. de 2013
large data means down sampling?
If it is the other case, you can interpolate row by row as in this example :
r=randn(30);
for n=1:30
G(n,:)=interp(r(n,:),22);
end
  1 comentario
Natalie
Natalie el 16 de Oct. de 2013
Sorry what I meant by large data I meant large in size, about 1000 rows and 100 columns. I wish to interpolate the data along the rows not columns, so interpolate the data present in each column of a row. Also I forgot to mention that there is also the problem of a lot of Nan values

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