Problem 328. Trickier Timing

Solution 43099

Submitted on 16 Feb 2012 by @bmtran (Bryant Tran)

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@bmtran (Bryant Tran) on 16 Feb 2012

tricky timing indeed

Test	Status	Code Input and Output
1	Pass	%% y=timing(1); y = datevec(now); y=mod(round(y(6)),5); assert(isequal(y,0))

Test

Status

Code Input and Output

Pass

%% y=timing(1); y = datevec(now); y=mod(round(y(6)),5); assert(isequal(y,0))

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