Find the number of cells in a bioreactor after a given time when doubling time is dd and initial number of cells is x.
So if t = 5000, dd = 100, x = 5 (x = [5000 100 5])
cells = 5629499534213120
Search online for the equation for this problem.
Solution Stats
Problem Recent Solvers77
Suggested Problems
-
Determine whether a vector is monotonically increasing
12036 Solvers
-
2085 Solvers
-
Sum the real and imaginary parts of a complex number
90 Solvers
-
160 Solvers
-
136 Solvers
More from this Author27
Select a Web Site
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
Select web siteYou can also select a web site from the following list:
Americas
- América Latina (Español)
- Canada (English)
- United States (English)
Europe
- Belgium (English)
- Denmark (English)
- Deutschland (Deutsch)
- España (Español)
- Finland (English)
- France (Français)
- Ireland (English)
- Italia (Italiano)
- Luxembourg (English)
- Netherlands (English)
- Norway (English)
- Österreich (Deutsch)
- Portugal (English)
- Sweden (English)
- Switzerland
- United Kingdom (English)
Problem Tags