vpa(factorial(27)) = 10888869450418351940239884288
no trailing zeros
factorial(27) = 1.088886945041835e+28
vpa(factorial(27)) - 1.088886945041835e+28 - 2.199023255552000e+12 = 0
I don't get it.
if vpa(factorial) = 10888869450418351940239884288
then there are no trailing zeros...
vpa(factorial(11)) = 39916800
two trailing, like in your problem statement...
am I crazy?
Highphi, any factorial equal to or greater than 5! has to have trailing zeros because it will have one or more pairs of 2 and 5 in its factors. I think factorial(vpa(27)) will give the correct value.
Factorize THIS, buddy
Hard limit function
Smallest n, for n! to have m trailing zero digits
Equal temperament - musical notes and frequency
Fractal: area and perimeter of Koch snowflake
The last non-zero digit of a factorial
Under the sea: Snell's law & total internal reflection
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