Caculate the area of below ellipse.
.So, input x = [a b], numeric vector when a, b are not zero.
Solution Stats
Problem Comments
2 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers64
Suggested Problems
-
Back to basics 12 - Input Arguments
619 Solvers
-
1252 Solvers
-
Is this triangle right-angled?
6530 Solvers
-
1708 Solvers
-
188 Solvers
More from this Author2
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
I think the problem answer is incorrect.
The area is pi*a*b for a standard ellipse (x^2/a^2 + y^2/b^2 = 1)
and not the one that is mentioned. So according to the problem statement, the answer should be pi*sqrt(a*b)
Thank you Dyuman.
I missed the terms of the square.
I modified the form of the ellipse equation.