Write a function that takes an integer n and finds the smallest integer m whose factorial is divisible by n. For example, if
, then the smallest factorial that is a multiple of n is 5! = 120; therefore,
.
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Chris, please check test 21. The factors of 1535238 include two 67's, therefore it seems to me the solution should be 134.
David: Take another look. ChrisR's anti-lookup trick lets correct solutions pass the test!
David, you are correct for Kempner(1535238), but that test asks for Kempner(Kempner(Kempner(1535238))).
Unfortunately, it does not stop lookup tables since 134 factors to 2 and 67, which means it obtains the same result as a lookup table. Kempner(Kempner(Kempner(1535238))) will do 134 -> 67 -> 67 and a lookup table 67->67->67.
May I suggest using Kempner(Kempner(Kempner(123456787654321))+10) as a test against lookup tables?