The dot product relationship, a dot b = | a | | b | cos(theta), can be used to determine the acute angle between vector a and vector b ( 0 to pi ).
The definition of | a | is ( a(1)a(1)+a(2)a(2)...+a(n)a(n) )^0.5.
The definition of "a dot b" is a(1)b(1)+a(2)b(2)...+a(n)b(n). (wikipedia)
In 3-D the angle is in the plane created by the vectors a and b.
The input may be a 2-D or a 3-D vector. These represent physical models.
An extension of this angular determination given vectors problem is to provide two points for each vector. The practical application relates to Laser Trackers which best fit multiple points for lines, surfaces, annular surfaces, and other reference points.
Examples:
a=[1 0] (x-axis); b=[0 1] (y-axis) which intersect at 90 degrees (pi/2)
theta=acos(a dot b/(|a||b|)=acos(0/(1*1))=pi/2 radians
a=[1 1 0] 45 degrees in xy plane b=[1 1 1.414] 45 degree vector in Z above a 45 degree rotation in XY plane.
theta=acos(a dot b/(|a||b|)=acos(2/(1.414*2))=pi/4 radians
Solution Stats
Problem Comments
Solution Comments
Show commentsProblem Recent Solvers527
Suggested Problems
-
Matrix indexing with two vectors of indices
775 Solvers
-
Find out missing number from a vector of 9 elements
322 Solvers
-
Given a matrix, swap the 2nd & 3rd columns
1264 Solvers
-
6029 Solvers
-
1155 Solvers
More from this Author309
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Spookily similar to Problem 381 ("Angle between two vectors")....