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Harsha K


Last seen: casi 3 años hace |  Con actividad desde 2017

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Times 2 - START HERE
Try out this test problem first. Given the variable x as your input, multiply it by two and put the result in y. Examples:...

alrededor de 3 años hace

Pregunta


Find square cell centres in a noisy checker board/chess board image using pattern detection
Dear all, I have a checker board/chess board pattern detection problem. I am interested in knowing the centres of the squares i...

casi 5 años hace | 1 respuesta | 0

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For Mac OSx Matlab - BASLER GenTL Producer Drivers for USB3 cameras
Hello all, Until today, I have not come across GenTL Producer Drivers for USB3 Basler cameras comaptible with any version of Ma...

más de 5 años hace | 0 respuestas | 3

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Simulink to create app that will acquire images from an external camera connected to an Android phone
I am creating a Simulink app that will be ported onto an Android phone. On demand, it shall acquire images from an external came...

más de 5 años hace | 0 respuestas | 0

0

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Make the vector [1 2 3 4 5 6 7 8 9 10]
In MATLAB, you create a vector by enclosing the elements in square brackets like so: x = [1 2 3 4] Commas are optional, s...

más de 5 años hace

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Interface and control FLIR (BlackFly S) with Matlab 64-bit platform code
Hello Mathworks team, This is a follow up on @Zoran Popovic's comment here: <https://www.mathworks.com/matlabcentral/answers/...

más de 6 años hace | 2 respuestas | 5

2

respuestas

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Matrix inversion using "pinv" or any other technique
I am trying to solve a system of independent linear equations. Ax = B for x. Many functions within Matlab achieve this wit...

más de 6 años hace | 2 respuestas | 1

2

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Problem with definite integration using integral(). Infinite or Not-a-Number value encountered.
Hi all, I just solved this problem by centering the x-axis in the computational space within the evaluation interval. As i...

alrededor de 7 años hace | 0

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Moving a curve in one axis to ascertain area under the curve is zero
Dear Teja, Dear John, Thank you very much. I solved it in the following way: I defined a function for finding it using sy...

alrededor de 7 años hace | 0

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Moving a curve in one axis to ascertain area under the curve is zero
Hi Folks, Following is my function: % where pd_def = defined constant which keeps changing for different situations %...

alrededor de 7 años hace | 3 respuestas | 0

3

respuestas

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Problem with definite integration using integral(). Infinite or Not-a-Number value encountered.
Hello, This is my function definition. function E_j = E_fld_integ(facet_flag, pd, lower_limit, upper_limit) F...

más de 7 años hace | 2 respuestas | 0

2

respuestas

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Problem with definite integration using integral(). Infinite or Not-a-Number value encountered.
Hi all, By the way, I want to achieve the desired result without using the symbolic toolbox as: firstly I do not have the lic...

más de 7 años hace | 0