Community Profile

photo

Lemuel Carlos Ramos Arzola


PhD student at INRS, Canada

Last seen: 11 meses hace |  Con actividad desde 2019

Followers: 0   Following: 0

Estadísticas

All
  • Thankful Level 2
  • Solver
  • First Review
  • Knowledgeable Level 1
  • First Answer
  • Thankful Level 1

Ver insignias

Feeds

Ver por

Respondida
Help Using Newton Rhapson Method for Colebrook equation
Hello Mary, The problem is with the function: diff(h(x)) This function operates with vectors and it only computes the differe...

alrededor de 4 años hace | 0

| aceptada

Respondida
How can overlay two contour plot in a subplot?
I found this solution Z1 = peaks; Z2 = peaks.^2; ax = subplot(2,1,1); hold on contourf(Z1,'--') colorLim = ax.CLim; con...

alrededor de 4 años hace | 1

| aceptada

Pregunta


How to set a legend with a label for two or more lines?
Hello, In the graphic legend I want to share the same label for two or more lines. For example, I have two (or more) pair of d...

alrededor de 4 años hace | 1 respuesta | 0

1

respuesta

Pregunta


How can overlay two contour plot in a subplot?
Hello, I am trying to plot and overlay two contour plots in the same figure but with some specifications. Both plots share the ...

alrededor de 4 años hace | 1 respuesta | 0

1

respuesta

Pregunta


Low quality when exporting graph in emf
Hello, The problem that happens to me is divided into two parts. 1. It happens that when I export a graphic in emf vector form...

alrededor de 5 años hace | 1 respuesta | 0

1

respuesta

Respondida
How can numerically compute eigenvalues of an ordinary differential equation in MATLAB?
Hello, Thanks for the answers. I found the same problem here: https://www.mathworks.com/matlabcentral/answers/405977-singula...

alrededor de 5 años hace | 0

| aceptada

Pregunta


How can numerically compute eigenvalues of an ordinary differential equation in MATLAB?
Hello, I need to compute (numerically) the eigenvalues (L) of this singular ODE, , subject to Is it possible to use t...

alrededor de 5 años hace | 3 respuestas | 0

3

respuestas