Koushik Vemula
MathWorks
Followers: 0 Following: 0
Estadística
0 Preguntas
10 Respuestas
CLASIFICACIÓN
2.543
of 300.765
REPUTACIÓN
24
CONTRIBUCIONES
0 Preguntas
10 Respuestas
ACEPTACIÓN DE RESPUESTAS
0.00%
VOTOS RECIBIDOS
5
CLASIFICACIÓN
of 21.084
REPUTACIÓN
N/A
EVALUACIÓN MEDIA
0.00
CONTRIBUCIONES
0 Archivos
DESCARGAS
0
ALL TIME DESCARGAS
0
CLASIFICACIÓN
of 170.941
CONTRIBUCIONES
0 Problemas
0 Soluciones
PUNTUACIÓN
0
NÚMERO DE INSIGNIAS
0
CONTRIBUCIONES
0 Publicaciones
CONTRIBUCIONES
0 Público Canales
EVALUACIÓN MEDIA
CONTRIBUCIONES
0 Temas destacados
MEDIA DE ME GUSTA
Feeds
Optimtool not enough arguments
According to my understanding you are facing this problem because of the way you are trying to access the function. You need...
casi 6 años hace | 0
Can I derive a dependent variable in Matlab?
According to my understanding you want to create a variable ‘y’ which is dependent on variable ‘x’ You can do it using ‘syms’...
casi 6 años hace | 1
| aceptada
cumulative maximum loss code
According to my understanding you have a variable ‘x’ which has ‘n’(say) number of values. You would like to find the value of...
casi 6 años hace | 0
Make probability matrix from data set
According to my understanding, you’d like to have a matrix (say ‘Prob’) which stores the data values in an n-by-3 matrix where f...
casi 6 años hace | 0
how to access compass formatting details?
In MATLAB there is a "polarplot" function that allows you to update the properties of the polar axes. Please see the following d...
casi 6 años hace | 1
How can I convert this pseudo code to matlab?
According to what I understand the pseudo code you’ve written is correct with some minor points to be taken under consideration....
casi 6 años hace | 0
Manipulating matrix with 'for' loop
According to what I understand you want to change the values of 'main diagonal’ and ‘adjacent diagonals’ of the given matrix. ...
casi 6 años hace | 0
Find n for inverse of e approximation
According to what I understand, you are trying to get the value of ‘accurate_n’ which gives you a tolerance of ‘0.0001’. The pro...
casi 6 años hace | 0
| aceptada
How to take a derivative of x with respect to time.
According to what I understand, you are trying to get the differentiation of variable ‘o’ with respect to the parameter ‘t’. ...
casi 6 años hace | 0
Why does x(x+y) dy give a x^3 component?
Both answers are correct. d/dy[ x*(x+y)^2/2 ] = d/dy[ (x^3)/2 + x^2*y + y^2*x/2 ] = x*(x + y) d/dy[ x*y*(2*x+y))/2 ] = x*(x ...
casi 6 años hace | 3
| aceptada

