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Programming in MATLAB applied to interdisciplinary engineering fields

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fprintf with warning of a lone trailing backslash
folderName = strcat(rootFolder,filesep,timeSteps(m+2).name); fprintf(['\nProcessing folder %s', folderName]); You need ...

alrededor de 6 horas ago | 1

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I dont get why I am encountering an error message when running this code.
%v_t=20; %v_i=1; %g=10; %expo1=-2*g*t./v_t; %expo2=-2*g*t./v_i; %function I want to integrate and plot:v_t*(1-exp(expo1)+v_...

1 día ago | 0

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code no good :(
clc,clear all %% Load Data - Initilize Variables DP980TD_S2 = xlsread('DP980TD-S2.xlsx'); % Data File % Constants widthO...

2 días ago | 0

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How can I get the value by choosing 't' and 'x'? ,How should I set the graph range?
L = 30; n = 10; T0=500; T1s=300; T2s=400; dx=L/n; alpha=0.000085; t_final=4800; dt=300; % use a coarse timestep ...

2 días ago | 0

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Using nested FOR() loops to populate a matrix
% MacLaurin Series of e^x format longG % define vector to hold series x values X = 0 : 0.01 : 1; % Create matrix to co...

2 días ago | 1

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how to write a function for quadratic equation?
if (d>=0) & (~(a==0)) use binary operator &

4 días ago | 0

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Why is my loop not working? "Index exceeds array bounds"
%%%%%% DEFINITIONS %%%%%%% clear Q_lpm=15; Q(1) =(Q_lpm/1000)/60; %m3/s [INPUT] diameter = 0.01; % m [INPUT] t =0.01; % tim...

4 días ago | 0

Answered
interpolate (extrapolate?) the values in between two matrices using existing data
A = [1, 2, 3, 4, 5; 0.3654, 0.3634, 0.3663, 0.3665, 0.3677]; B = [16, 17, 18, 19, 20; 0.4653, 0.4636, 0.4652, 0.4620, 0.4715];...

7 días ago | 0

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Answered
I'm definitely doing the exponential distribution wrong, am I?
N = 1e4; a=0; b=1; x = (a+(b-a)*rand([N,1])); lambda = 11; % try with different lambda values Y = -log(x)/lambda; figure...

9 días ago | 0

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speed up the for and if loop
for i = 1:10:300 % use step increments for j = 1:10:500 for k = 1:1000:17000 if(temp(i,:) > 2) ...

13 días ago | 0

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ode45 keeps giving me the error shown below.
a = 0.459; lambda1 = 1.11*10^(-2); %units min^-1 lambda2 = 1.38*10^(-4); %units min^-1 Cp0 = 100; %units nM t = 0:7200; %uni...

13 días ago | 0

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Answered
ODE with Newton method
clear all close all n=1001 y0=1; xmin=0; xmax=10; x=linspace(xmin,xmax,n); %grid step=(xmax-xmin)/n; %Step Size yy=zer...

14 días ago | 0

Answered
Function output an array
in = [rand(1,15);rand(1,15)]; differences(in) function [out] = differences(in) %This function allows an array input and th...

alrededor de 1 mes ago | 0

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During simulation of mathematical model occuring following error
Use limit output option for selecting integrator saturation limits. May be in your case, its running indefinitely.

alrededor de 1 mes ago | 0

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Using function with a for loop
(factorial(i)).^2) You have two extra parenthesis for this term

alrededor de 1 mes ago | 0

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Answered
Index location of certain dates with find and a loop
locs= zeros(length(TargetDates),length(t_list)); % change preallocated array size Change the preAllocated size of locs locs...

alrededor de 1 mes ago | 0

Answered
why my code is running so slowly in the while loop
clc; clear all; close all; r = 1250; O = [2500 2500] Px = 2500; Py = 1000; P = [ Px Py ]; Va = 100; To = 4; q22 = 0.1 ...

alrededor de 1 mes ago | 0

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Summation of all odd numbers from 1 to 451
n = 451; a = 1; d = 2; S = 0; % Compute S by adding the terms for i = 1:n S(i) = (a+(i-1)*d/2); end sum(S(1:2:end)) ...

alrededor de 1 mes ago | 1

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Implementation of Integral Cost function in Matlab
tspan = [0,1]; x0 = 1; u = 0.1; tau = 1; xn = 1; % noise [time, dxdt, J] = plant_dynamics(tspan,x0,u, tau, xn); subplot...

alrededor de 1 mes ago | 0

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Answered
Problem with filling a variable inside loops
p = readtable ('pnts.txt'); p = table2array(p); x_p=p(:,2); y_p=p(:,3); z_p=p(:,4); t_p=p(:,5); xedges=-100:10:100;...

alrededor de 2 meses ago | 0

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Answered
Numerical solution of PDE with uniform initial condition
clear all clc %% pts = 2^0.1; tmax = 1.76; ti = linspace(0,tmax,50); % give suitable sample size xi = linspace(0,1,50); ...

alrededor de 2 meses ago | 1

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Answered
Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters. Can anyone help in this error?
M = 1:10; R = 200:300; Mean = mean(M); Range = mean(R) d = 2.326; n = 5; SE = Range./(d*sqrt(n)) % check the parenthesis ...

alrededor de 2 meses ago | 0

Answered
Iterations outcome summation (accumulation).
x = [4 7 9 11 6 8 13 5 0 2 1 23;14 3 8 0 2 9 7 2 12 17 4 5;0 1 3 4 0 0 7 8 2 5 4 1]; d = 0; iter = 1; for k = 1:size(x,1) fo...

alrededor de 2 meses ago | 0

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Answered
Arrays have incompatible sizes for this operation.
LeqPrevious = zeros(1,30,2); % array preallocation is not the sme size of Leq LeqPrevious = Leq(i,:,:); % inside the loop Leq...

alrededor de 2 meses ago | 0

Answered
Solve System of ODEs with Multiple values of a parameter using vectorization but not looping.
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%...

2 meses ago | 0

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Answered
Legend Producing Wrong Colour Lines
x=-5:0.1:5; freal=x.*exp(-x); ftaylor0= 1./exp(x); % they is scalar in your code ftaylor1= 1./exp(-x); % this is scalar in ...

2 meses ago | 0

Answered
I've tried to make a simulation with matlab but it can't work. especially for the function commands that I have described. I'm not good at matlab. can you help me to check the
clc;clear all;format long; y = [1000 0 0 2000 0]'; [T y]=ode45(@fgliom,[0 200],[10000 0 0 2000 0]',10^-7); [T0 y0]=ode45(@f...

2 meses ago | 0

Answered
When plotting ROC curve; test_labels=double(nominal(imdsTest.Labels)); I am getting an error as " Unrecognized function or variable 'nominal' .
test_labels = nominal(imdsTest.Labels); double(test_labels) % try this If you have defined function named nominal in your p...

2 meses ago | 0

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Answered
regexp shows an error while reading a space in text file.
ss = 'PORT 12 P=2 Z=50 PIN_ID=CB7TX' [port_tokens2,port_match3] = regexp(ss,'PORT\s+(\d+)\s+(\w+=\d)+\s+\w+=\d+\s+(\w*=\w*)',...

2 meses ago | 1

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Answered
Error: The length of the segments cannot be greater than the length of the input signal.
fft_point = [2048 4096]; fft_point must have atleast 2 values as input argument for _pwelch_ function

2 meses ago | 1

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