A very basic question about nested for loops
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    Negar
 el 26 de Oct. de 2013
  
    
    
    
    
    Respondida: Bhavini Sarkar
      
 el 17 de Sept. de 2016
            Hello all,
There are 2 persons, which each are pronouncing 9 vowels 10 times (I have in total 2*9*10 sound files). I've derived 2 features (F1 and F2) for each repetition of each vowel for all speakers, and now Im trying to compute mean and covariance for them . Here is where Im stuck: The sigma_est should result in 9 matrices of size 2x2 (as there are 9 vowels) , while it is just of size 2x2. It seems that the outset loop doesn't work properly to make 9 iterations of inner loops. What should I do in order to make it done? Thanks !
Here is the code:
Nvow = 9; % number of vowels
Nrep = 10; % number of repetition for each vowel
Nspeak = 2; % number of speakers in the group
   for i=1:Nvow
       for k=1:Nspeak
           for j=1:Nrep  
               F1(i,k,j) = features_tst((k-1)*Nvow*Nrep+(i-1)*Nrep+j).value(1);
               F2(i,k,j) = features_tst((k-1)*Nvow*Nrep+(i-1)*Nrep+j).value(2);
           end
       end
       F11=reshape(squeeze(F1(i,:,:)),20,1);
       F22=reshape(squeeze(F2(i,:,:)),20,1);
       mu_est_F1 = sum(F11)/(Nrep*Nspeak);
       mu_est_F2 = sum(F22)/(Nrep*Nspeak);
       F=[F11 F22];
       mu_est=[mu_est_F1 mu_est_F2];
       sigma_est=cov(F);
   end
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Respuesta aceptada
  sixwwwwww
      
 el 26 de Oct. de 2013
        Dear Negar, re-write the last line as follows:
sigma_est{i} = cov(F);
Then sigma_est will contain 9 matrices of 2x2 size in a cell array. I hope it helps. Good luck!
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