Why do I get NAN?
191 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Yasmin Tamimi
el 19 de En. de 2014
Comentada: Dheeraja Karthikeyan
el 25 de Abr. de 2020
Hey everyone,
I'm running this equation
hMphi(1) = - (dd_Anis(1) * ddu_acos(1) * du_dMphi(1))/(C2*sin(Mtheta(1)))- ((Is*P_hbar/(2*P_Q*g*C2))*((ephix(1)*Ffx(1))+(ephiy(1)*Ffy(1))))- Ms*(Ny-Nx)*sin(Mtheta(1))*sin(2*Mphi(1))+ (Happy*cos(Mphi(1)) - Happx*sin(Mphi(1))) ;
in a loop and a certain point the value of this vector becomes a NAN?! Can Anyone tell me why is this happening? I' dividing by a sin, so I thought that maybe the problem is from it, but I printed the values of it I didn't get Inf.
Thanks
0 comentarios
Respuesta aceptada
Roger Stafford
el 19 de En. de 2014
Any of these arithmetic operations will produce a NaN: zero/zero, zero*infinity, infinity/infinity, infinity-infinity. For example, if any of the three quantities, dd_Anis, ddu_acos, or du_dMph were to become zero at the same time that sin(Mtheta) is zero, that would produce a NaN. You should make a test on hMphi each time it is computed and arrange to stop if a NaN is detected so you can check all the values that go into your equation at that point.
0 comentarios
Más respuestas (2)
Jan
el 19 de En. de 2014
You can stop the code automatically, when the NaN appears:
dbstop if naninf
Then inspect the local variables and evaluate the different parts of the equation in the command window until you find the reason for the NaN.
1 comentario
Anna
el 19 de En. de 2014
Have you tried to isolate the part of the equation where the fault is at? Debug the equation in the loop iteration before the equation turns into a NaN.
0 comentarios
Ver también
Categorías
Más información sobre Elementary Math en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!