repeating an index number n times in a vector

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Siem Nijskens
Siem Nijskens el 23 de En. de 2014
Comentada: Siem Nijskens el 23 de En. de 2014
Hi People,
I'd like to transform a vector p like this one. p=[3 0 2 2 1 0 3]
Into a new vector that has n times the indexnumber of n, for example:
new vector: v=[1 1 1 3 3 4 4 5 7 7 7] so it has 3 times 1, zero times 2, 2 times 3 and so on.
the numbers generated in p are variable but are always between 0 and 15
I hope you can help me.
Regards, Siem

Respuesta aceptada

Amit
Amit el 23 de En. de 2014
v = [];
count = 1;
for j = 1:length(p)
if p(j) ~= 0
v(count:count+p(j)-1) = j*ones(p(j),1);
count = count + p(j);
end
end
  1 comentario
Siem Nijskens
Siem Nijskens el 23 de En. de 2014
Hi Amit,
Thank you so much this has been driving me crazy but your solution works perfectly.
Regards, Siem

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Más respuestas (1)

Chris
Chris el 23 de En. de 2014
Hey Siem,
I would do it like this:
v = p .* 1:length(p);
  1 comentario
Siem Nijskens
Siem Nijskens el 23 de En. de 2014
Hi Cris,
Thanks for answering my question, unfortunately your solution didn't work.
Regards, Siem

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