using arrayfun for a function with multiple inputs

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Michael
Michael el 26 de En. de 2014
Comentada: Anik Hirenkumar Shah el 27 de Feb. de 2020
I want to call my Before function with a 1 x 40 structure called struct for the s input, a value of 0 for the begins input, and a value of 20 for the ends input, but I can't figure out how to make it work with arrayfun correctly.
Here's what I have now, and the error that it gives me is at the bottom:
x = arrayfun(@Before, [struct,0,20]);
function v = Before(s,begins,ends)
Numbers = s.H;
firstColumn = Numbers(:,1);
rowsUnder = (firstColumn>begins)&(firstColumn<ends);
sNumNew = Numbers(rowsUnder,:);
v = mean(sNumNew(:,3));
end
Error using horzcat
The following error occurred
converting from double to
struct:
Error using struct
Conversion to struct from double
is not possible.
Error in ComparingMeans (line 22)
x = arrayfun(@Before,[struct,0,20]);

Respuesta aceptada

Matt J
Matt J el 26 de En. de 2014
Editada: Matt J el 26 de En. de 2014
Multiple arrayfun arguments should not be concatenated. You need to do
x = arrayfun(@Before, myStructure, 0 , 20);
Since "struct" is also the name of a built-in MATLAB function, you will minimize coding hazards if you use a different name for it, like I did.
  3 comentarios
Matt J
Matt J el 26 de En. de 2014
Editada: Matt J el 26 de En. de 2014
Instead of passing scalars for 0 and 20, you'll have to pass vectors of the same length as myStructure
d=size(myStructure);
a=zeros(d);
b=a;
b(:)=20;
x = arrayfun(@Before, myStructure, a, b);
That's very strange. I thought arrayfun did scalar expansion. That might be only for gpuArrays....
Michael
Michael el 26 de En. de 2014
ah thanks, it works now

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Más respuestas (1)

Andrei Bobrov
Andrei Bobrov el 26 de En. de 2014
b1=0;
e1=20;
x = arrayfun(@(x1)Before(x1,b1,e1), your_structure)
  2 comentarios
Michael
Michael el 27 de En. de 2014
Yes, this also works, thanks
Anik Hirenkumar Shah
Anik Hirenkumar Shah el 27 de Feb. de 2020
this worked for me as well. Thanks

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