Converting HEX to uint8

Hello I want to convert a very long HEX-String into the uint 8 format because i want so send the uint8 signal through an RS-232 device.

The first step i did, was converting the HEX-String in a decimal number with the hex2dec('HEX-String'. After that i used the uint8 ('previousresult').

My Problem is, that the HEX-String is too long and results in a decimal number of about 1*10^93 this leads to an data-overload.

Can anyone help me?

Thanks a lot!

Greetings

[Patrik Ek]

You may want to split up the string into smaller parts. the largest uint8 allowed is 255 (which you probably knew). What you want to have then is something on a format,

 original = 'aabbccdd';
 wanted = ['aa';'bb';'cc';'dd'];

Answer 1

[Patrik Ek]

Try to reshape it first. You of course only want to send in 2hex at a time since the largest unit8 is 255. Try this,

 hexstring = 'aabbccddee';
 reshapedString = reshape(hexstring,2,5);
 hexMtx = reshapedString.';
 disp(hexMtx);
 decMtx = hex2dec(hexMtx);
 disp(decMtx);
 intVector = uint8(decMtx);
 disp(intVector);

This will give you an uint8 column vector. If you want it as a string format (the uint8 vector) then do,

 intString = num2str(intVector');
 intString = strrep(intString,' ','');

Good luck and comment if questions.

[David]

thanks!