What's wrong with my feature extraction code?

I am getting same descriptors for different images.
I tested it by:
image1 = imread('C:\Users\Explorer\Documents\MATLAB\ASL_signs\A.jpg');
image2 = imread('C:\Users\Explorer\Documents\MATLAB\ASL_signs\B.jpg');
v1=Descrip(image1);
v2=Descrip(image2);
SUM=sum(v1-v2)
_____________________________________________________________________________________
Output :
SUM =
0

1 comentario

Explorer
Explorer el 12 de Feb. de 2014
There is something wrong in Descrip.m because I am getting zero for SUM=sum(v1-v2). Ideally, it should not be zero.

Respuestas (2)

David Young
David Young el 12 de Feb. de 2014

0 votos

Descrip writes then reads contour.jpg, and then computes the result from that. One way to set about debugging would be to see whether contour.jpg is different for the two images. That will help pin down where the problem lies.

4 comentarios

Explorer
Explorer el 12 de Feb. de 2014
Editada: Explorer el 12 de Feb. de 2014
How can I program it to save figure with different name whenever I run it?
I created another function having name "Descrip2.m" in which image will be saved with contour2.jpg
And tested again by
image1 = imread('C:\Users\Explorer\Documents\MATLAB\ASL_signs\A.jpg');
image2 = imread('C:\Users\Explorer\Documents\MATLAB\ASL_signs\B.jpg');
v1=Descrip(image1);
v2=Descrip2(image2);
SUM=sum(v1-v2)
__________________________________________________________________________________
Output:
SUM =
0
____________________________________________________________________________
Still I am getting sum as zero.
Explorer
Explorer el 12 de Feb. de 2014
Editada: Explorer el 12 de Feb. de 2014
But sum is not equal to equal when I replace "1" with "2" in line # 57 of Descrip.m and Descrip2.m
i.e
________________________________________________________________________
Original
thisBoundary = boundary{1}; % Or whatever blob you want.
________________________________________________________________________
Replaced
thisBoundary = boundary{2}; % Or whatever blob you want.
David Young
David Young el 13 de Feb. de 2014
The idea was that you run Descrip with one input image, look at contour.jpg, run it again with the other input image, and look at contour.jpg again. Are they different?
Image Analyst
Image Analyst el 12 de Feb. de 2014
Editada: Image Analyst el 12 de Feb. de 2014

0 votos

Don't use image as a variable name - it's the name of a built-in function.

5 comentarios

Explorer
Explorer el 13 de Feb. de 2014
I have renamed it but still there occur same problem.
Image Analyst
Image Analyst el 13 de Feb. de 2014
Editada: Image Analyst el 13 de Feb. de 2014
What are you using now: Descrip or Descrip2? Doesn't stepping through it with the debugger reveal where the problem is????
Explorer
Explorer el 13 de Feb. de 2014
Editada: Explorer el 13 de Feb. de 2014
image1 = imread('C:\Users\Explorer\Documents\MATLAB\ASL_signs\A.jpg');
image2 = imread('C:\Users\Explorer\Documents\MATLAB\ASL_signs\B.jpg');
v1=Descrip(image1);
v2=Descrip(image2);
SUM=sum(v1-v2)
___________________________________________________________________________________
Output :
SUM =
0
_____________________________________________________________________
I think sum should not be zero here. Don't you think so?
Image Analyst
Image Analyst el 13 de Feb. de 2014
If image A equals image B then I think they should be the same. You didn't attach either image so only you can know that. What did stepping through with the debugger reveal to you?
Walter Roberson
Walter Roberson el 13 de Feb. de 2014
Watch out for the case where v1 and v2 are being returned as unsigned integers; in that case if v2 > v1 you would get "clipping" at 0 instead of getting a negative number.

La pregunta está cerrada.

Preguntada:

el 12 de Feb. de 2014

Cerrada:

el 20 de Ag. de 2021

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