Removing characters from/breaking up file names
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B.M.
el 16 de Feb. de 2014
Comentada: Image Analyst
el 16 de Feb. de 2014
Hello all,
I have a list of file names from which I'd like to remove some characters. Ideally, I'd like to break up the file name into parts, but can't figure out how to do that (aside from fileparts, which was useful in removing the extension). Here's an example:
02-Feb-2009_1.xls ------------------------------------- 02-Feb-2009_1
02-Feb-2009_2.xls ----after file parts ext removal----> 02-Feb-2009_2
02-Feb-2009_3.xls ------------------------------------- 02-Feb-2009_3
I would like to separate the names into dates and trial numbers (in different columns):
02-Feb-2009_1 -------------------------------------- 02-Feb-2009 / / 1
02-Feb-2009_2 --------------?--?--?----------------> 02-Feb-2009 / / 2
02-Feb-2009_3 -------------------------------------- 02-Feb-2009 / / 3
I have tried taking the length of the names, then subtracting 2 or 3, but I can't figure out how to apply that new length to each cell in the file.
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Respuesta aceptada
Mischa Kim
el 16 de Feb. de 2014
Editada: Mischa Kim
el 16 de Feb. de 2014
str = '02-Feb-2009_1.xls';
str_trim = str(1:strfind(str,'.')-1)
str_trim =
02-Feb-2009_1
or, for the latter part
str = '02-Feb-2009_1';
str_1 = str(1:strfind(str,'_')-1)
str_1 =
02-Feb-2009
str_2 = str(strfind(str,'_')+1:end)
str_2 =
1
Más respuestas (1)
Image Analyst
el 16 de Feb. de 2014
What about using the fileparts() function?
2 comentarios
Image Analyst
el 16 de Feb. de 2014
Sorry - I didn't read closely enough. I guess you need to do custom parsing like Mischa showed. I often do that too.
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