Loop that creates arrays

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Brian
Brian el 10 de Feb. de 2011
Respondida: Hillary Omuga el 31 de En. de 2020
Hey folks I'm trying to write a loop that will create arrays filled with zeros and I'd like it so that each array can be identified somehow (i.e. subscripts, unique name for each array).
In Maple, I would have done something like this... for k to 10 do A[k] := Array(1..10): end do:
which would create 10 arrays and each could be indivually accessed using A[k]. (i.e. A[1] is an array of size 10, A[2] is a different array of size 10 etc...)
Is there a way to do this in Matlab?

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Jos (10584)
Jos (10584) el 10 de Feb. de 2011
If all the arrays are vectors (=1D arrays in matlab) you can store them in a matrix (=2D array).
% Pre-allocate an matrix with four "vector arrays" of 6 elements each
A = zeros(4,6) ;
Here is an example to fill this array
for k=1:4
A(k,:) = (1:6) ./ k ; % just an example
end
To access a "array" (vector!) use indexing B = A(2,:) % get second row
If the vectors have different sizes, you need to look into cells and/or structs
A = {1:3 1:10 1:5} % a cell with 3 vectors
A{3} % third vector
  2 comentarios
Walter Roberson
Walter Roberson el 10 de Feb. de 2011
Small modification: instead of
A(k,:) = [1:6) / k;
better is
A(k,:) = (1:6) ./ k;
1:6 is automatically a vector and does not need [] around it. And using ./ instead of / is good practice as is makes it clearer that you are expecting element-by-element division rather than matrix division.
Jos (10584)
Jos (10584) el 11 de Feb. de 2011
I completely agree, Walter. I have changed the answer accordingly.

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Más respuestas (3)

Sean de Wolski
Sean de Wolski el 10 de Feb. de 2011
doc cell
You need cell arrays.

Brian
Brian el 10 de Feb. de 2011
Ok great thanks for that.
I think I'll go with Jos' option as all vectors should be the same size.
  1 comentario
Walter Roberson
Walter Roberson el 10 de Feb. de 2011
These remarks are better done as Comments on the appropriate answer.

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Hillary Omuga
Hillary Omuga el 31 de En. de 2020
write a for loop to create an array named X. Each value in X is equal to its assaciated index value (a.k.a its position in the array) times 12 minus 1. The size of X is 52*1

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