TF function on Simulink

Hello I am trying to create a MATLAB function on simulink that ,between others, requires the use of the 'tf' function . Problem is I can't really find a way to use the output of the 'tf' function since it's an mxarray. So when I run something like this
function y = fcn(u)
%#codegen
coder.extrinsic('tf')
g=tf([1],[1 1]);
y=0;
y=g*u;
I get this error: MATLAB expression 'mtimes' is not numeric. Block MATLAB Function (#36) While executing: none . Initializing g gives me the 'is not numeric' error so it won't help... So I was wondering if there is anyway to get it done - the scripting way, I know I can use transfer function simulink blocks etc...Thanks in advance. (I am using Matlab R2012b btw)

4 comentarios

Azzi Abdelmalek
Azzi Abdelmalek el 28 de Feb. de 2014
Editada: Azzi Abdelmalek el 28 de Feb. de 2014
What do you want to do?
Manos
Manos el 28 de Feb. de 2014
I want to get a transfer function from a simulink matlab function using 'tf' like in the code I quoted .
Manos
Manos el 28 de Feb. de 2014
Editada: Manos el 28 de Feb. de 2014
What I am asking is : If there wasn't a "Transfer Function" block on Simulink already , how would you "design" it manually using a matlab function block?
Ryan Rizzo
Ryan Rizzo el 21 de Mzo. de 2018
Hi Manos, how did you manage to solve this issue?

Iniciar sesión para comentar.

Respuestas (1)

Rick Rosson
Rick Rosson el 28 de Feb. de 2014

0 votos

Multiplication is not the same thing as convolution. This approach will not work. You need to write a function that performs continuous time convolution. The only way to do that is to approximate the solution by approximating the continuous integral as a discrete summation over a small sample size. It should be possible, but not easy or fun.
Why not just use the TF block provided by a Simulink? No sense reinventing the wheel.

1 comentario

Manos
Manos el 28 de Feb. de 2014
But since G is in the frequency domain isn't multiplication correct? Why would I have to use convolution??? (I know it makes absolutely no sense trying this the long way, I am just really stubborn :P ) Thanks a lot for your answer Rick!

Iniciar sesión para comentar.

Preguntada:

el 28 de Feb. de 2014

Comentada:

el 21 de Mzo. de 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by