Four indexing matrix

I have a matrix nxn, each element is described by a 2 index number (i.e. one number for the column, one for the row). The problem is that i want to access this matrix by a four digit indexing. Is there a way to do that?

3 comentarios

Oleg Komarov
Oleg Komarov el 21 de Jul. de 2011
What do you mean? You want to retrieve two points at the same time?
Nikolaos
Nikolaos el 22 de Jul. de 2011
no, i want to access a matrix not by 2 digits indexing but by 4 index indexing. For example i want to map A(k,l,m,n)->p(i,j) {where i==row, j=column of p matrix }
Jan
Jan el 22 de Jul. de 2011
There is an infinite number of possibilities to map "A(k,l,m,n)->p(i,j)". Please specify how {k,l,m,n} and {i,j} are connected.

Iniciar sesión para comentar.

 Respuesta aceptada

Nikolaos
Nikolaos el 22 de Jul. de 2011

0 votos

Ok, i made it. So, for a given matrix "pall" i go to a matrix "alpha(i,j,k,l)". For example: alpha(1,1,1,1)=pall(1,1)=1 alpha(2,2,2,2)=pall(4,4)=16 alpha(1,1,1,2)=pall(1,2)=2 .. p.s. If you have a faster solution please tell me. Thank you all
%this is the actual algorithm % pall=([1 2 3 4;5 6 7 8; 9 10 11 12; 13 14 15 16]); k=0 for n1=1:4 for n2=1:4 k=k+1 temp(k)=pall(n1,n2) end end k=0 alpha=zeros(2,2,2,2) for n3=1:2 for n4=1:2 for n5=1:2 for n6=1:2 k=k+1 alpha(n3,n4,n5,n6)=temp(k) end end end end %

5 comentarios

Nikolaos
Nikolaos el 22 de Jul. de 2011
pall=([1 2 3 4;5 6 7 8; 9 10 11 12; 13 14 15 16]);
k=0
for n1=1:4
for n2=1:4
k=k+1
temp(k)=pall(n1,n2)
end
end
k=0
alpha=zeros(2,2,2,2)
for n3=1:2
for n4=1:2
for n5=1:2
for n6=1:2
k=k+1
alpha(n3,n4,n5,n6)=temp(k)
end
end
end
end
Andrei Bobrov
Andrei Bobrov el 22 de Jul. de 2011
is better
permute(reshape(pall,[2 2 2 2]),[2,1,3,4])
Jan
Jan el 22 de Jul. de 2011
@Nikolaos: Please use code-formatting either by starting the code lines with 2 spaces or by marking the code section with the mouse and hitting the "{} Code" button in this page.
Nikolaos
Nikolaos el 22 de Jul. de 2011
Ok thanks a lot.. what needs to be change if for example the pall matrix is larger? fe 16x16
Walter Roberson
Walter Roberson el 22 de Jul. de 2011
Comments cannot be formatted yet, unfortunately.

Iniciar sesión para comentar.

Más respuestas (2)

Friedrich
Friedrich el 21 de Jul. de 2011

0 votos

Hi,
I am not sure what you mean with 4digit indexing. Do you want a 4d matrix?
>> a = zeros(3,3,3,3);
>> a(1,2,1,3)
ans =
0
Or do you like to pass 2 pairs of indices?
a = [1 2; 3 4]
%try to access 1,1 and 1,2
ind = sub2ind(size(a),[1 1],[1 2])
a(ind)
ans =
1 2

1 comentario

Nikolaos
Nikolaos el 22 de Jul. de 2011
i want to access a matrix not by 2 digits indexing but by 4 index indexing. For example i want to map A(k,l,m,n)->p(i,j) {where i==row, j=column of p matrix }

Iniciar sesión para comentar.

Jan
Jan el 22 de Jul. de 2011

0 votos

One example:
A = rand(3, 4, 5, 6);
p = reshape(A, 12, 30);
disp(A(2,3,4,5))
disp(p(8, 24))
Does this match your needs? Then SUB2IND and IND2SUB might help.

5 comentarios

Nikolaos
Nikolaos el 22 de Jul. de 2011
ok, i am a bit new to matlab, could be so kind of giving me an example using as a matrix the pall=([1 2 3 4;5 6 7 8; 9 10 11 12; 13 14 15 16])?
Andrei Bobrov
Andrei Bobrov el 22 de Jul. de 2011
pall=[1 2 3 4;5 6 7 8; 9 10 11 12; 13 14 15 16]
a = zeros(2,2,2,2)
a(:) = pall
Jan
Jan el 22 de Jul. de 2011
a = reshape(pall, 2,2,2,2);
Nikolaos
Nikolaos el 22 de Jul. de 2011
great thanks a lot
Nikolaos
Nikolaos el 5 de Oct. de 2011
but what if i have a matrix "pall" 100x100, or nxn .. ??
Thanx in andanve.

Iniciar sesión para comentar.

Categorías

Preguntada:

el 21 de Jul. de 2011

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by