how to find average value of floating numbers ??

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Lee
Lee el 11 de Mzo. de 2014
Comentada: Lee el 11 de Mzo. de 2014
Hello all,
I have an n-by-2 array comprised of floating numbers.
In the second column of this array, there are some arrays having same floating numbers.
I want to sort this array with respect to the second column and find the average value of the arrays having same floating numbers.
For example,
A = [0.33,0;0.53,0.2;0.433,0.2;0.11,0.5;0.95,0.4;0.99,0.5;0.32,0;0.44,0.3;0.38,0.4;0.62,0.1;0.23,0.4;0.44,0.5;0.76,0.5]
[B, I] = sort(A(:,2));
C = A(I,:)
Sorting was done successfully, and I tried to find the average of the arrays, using accumarray(subs,val). But, because ‘subs’ always requires positive integer, I can’t use this syntax in my case of accumulation of floating numbers.
Is there any solution for this? You may as well to use other syntax…
Thanks in advance

Respuesta aceptada

Sean de Wolski
Sean de Wolski el 11 de Mzo. de 2014
Editada: Sean de Wolski el 11 de Mzo. de 2014
Use unique to generate indices of unique floating point values
A = [0.33,0;0.53,0.2;0.433,0.2;0.11,0.5;0.95,0.4;0.99,0.5;0.32,0;0.44,0.3;0.38,0.4;0.62,0.1;0.23,0.4;0.44,0.5;0.76,0.5];
[uA,~,idxA] = unique(A(:,2)); % unique values and index
muA = accumarray(idxA,A(:,1),[],@mean); % mean of values at each index
[uA muA] % display
Also, you can use sortrows() to save yourself a step up above:
C = sortrows(A,2); %sort along second column

Más respuestas (1)

Andrei Bobrov
Andrei Bobrov el 11 de Mzo. de 2014
Editada: Andrei Bobrov el 11 de Mzo. de 2014
A = [0.33,0;0.53,0.2;0.433,0.2;0.11,0.5;0.95,0.4;0.99,0.5;0.32,0;0.44,0.3;0.38,0.4;0.62,0.1;0.23,0.4;0.44,0.5;0.76,0.5]
[a,b,c] = unique(A(:,2),'first');
[~,i0] = sort(b);
[~,i1] = sort(i0);
anew = a(i0);
c1 = i1(c);
out = [accumarray(c1,A(:,1),[],@mean),anew]

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