Symbolic DFFT in MATLAB?
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Hi Guys!
I'd like to ask for your help to execute symbolic discrete FFT on a 1D array containing integers (eg. [1 1]), then plotting its abs on a continuous interval. Is it even possible with the symbolic toolbox?
Thanks in advance, Ben0it8
1 comentario
Walter Roberson
el 17 de Mzo. de 2014
To check, you are only working with numeric values, but you want the result to be (e.g.) sin(42+cosh(19)) instead of the numeric equivalent ?
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Christopher Creutzig
el 31 de Mzo. de 2014
Editada: Christopher Creutzig
el 31 de Mzo. de 2014
I have no idea what “plotting its abs on a continuous interval” means, but you certainly can get a symbolic, exact, FFT from the Symbolic Math Toolbox:
>> feval(symengine, 'numeric::fft', [1 1], 'Symbolic').'
ans =
2
0
>> feval(symengine, 'numeric::fft', [1 1 2], 'Symbolic').'
ans =
4
1/2 + 2*((3^(1/2)*i)/2 + 1/2)^2 - (3^(1/2)*i)/2
- 3^(1/2)*i + ((3^(1/2)*i)/2 + 1/2)^2
1 comentario
Christopher Creutzig
el 24 de Ag. de 2021
Since somebody asked (please do use the questions feature here, instead of sending me email): There is no 'numeric:ifft', but you can use 'numeric::invfft'.
Note, however, that like anything involving feval(symengine, ..., this is considered an undocumented feature and can go away at any time. If this is functionality you regard useful and important for what you do, please do reach out to support@mathworks.com and let us know that you request “proper” support in the toolbox.
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