Borrar filtros
Borrar filtros

need to plot value of tau for changing value of angles help

2 visualizaciones (últimos 30 días)
Irenee
Irenee el 6 de Abr. de 2014
Comentada: Irenee el 7 de Abr. de 2014
clear % Homework D = diag(-rand(2,1)); % random diagonal matrix of 2 negatives eigenvalues v1 = rand(2,1); v2 = rand(2,1); %v1=v1/norm(v1); %v2=v2/norm(v2); V = [v1, v2]; r1=V(1,:); r2=V(2,:); %V = rand(2,2); % rotation matrix, the angle of rotation is pi/6 for k = 0:0.001:1/3 R = [cos(k*pi), -sin(k*pi); sin(k*pi), cos(k*pi)] k
r11 = r1*R;
r22 = r2*inv(R);
V1 = [r11;r22];
end %V1 = V*R A = V*D*inv(V); D1 = diag(-rand(2,1)); A1 = (V1)*(D1)*inv(V1); figure(1) p = (log(norm(inv(V)*V1)) + log(norm(inv(V1)*V)))/(-max(eig(A)) - max(eig(A1)))
plot(k,p) xlabel('k') ylabel('p')
can u help me to plot this ? the plot shows only a point in space thanks

Respuesta aceptada

ragesh r menon
ragesh r menon el 7 de Abr. de 2014
Here you are only storing last values of "k" and "p". And hence the plot shows a point. To modify the code, store value of k first. and the for loop should operate by calling "i". for example
for i=1:length(k)
R(i)=...
r11(i)=..
r22(i)=..
V1(i)=...
end.
this stores each of these values in an array and with these values you can find "p(i)"s. Now if you plot you should be able to meet your requirements

Más respuestas (0)

Categorías

Más información sobre Creating and Concatenating Matrices en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by