Ensuring that a number is present in a string?

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Andy
Andy el 10 de Abr. de 2014
Comentada: Andrew Newell el 10 de Abr. de 2014
I am writing a code that asks a user for a password, and it must satisfy the following conditions:
- at least 8 characters in length,
- have at least one capital letter, and one lowercase
- include a number
I have the top two figured out but I don't know how to write a function for the third. It is all in a "while" loop and a value of 1 is assigned to each condition... When all 3 are met, the "while" loop stops repeating.
How can I write the function that will determine if there is a number in the password the user inputs?
Thanks for the help!
  1 comentario
Andy
Andy el 10 de Abr. de 2014
Editada: Andy el 10 de Abr. de 2014
RE:
I am hoping to do something similar to what I did for the function that ensures a capital letter is present in the string. It will look better when written out similarly, in my opinion. Here is what I did for that function:
function [CAPS_check]=CAPS_check(password)
%CAPS_check ensures there is at least one capital letter in the password
%all(lower(password)==password) equal to one, then function has at least one CAP
CAPS_check=all(lower(password)==password);
end

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Andrew Newell
Andrew Newell el 10 de Abr. de 2014
Editada: Andrew Newell el 10 de Abr. de 2014
This can be solved nicely using MATLAB regular expressions. The idea is to look ahead from the start of the line to see if each of the criteria are met, and then to return any strings that match these criteria. If an empty string is returned, it is not a valid password.
function tf = isValidPasswd(str)
anchorToStartOfLine = '^';
atLeastEightChars = '(?=.{8,})'; % I'm assuming that any characters are allowed
atLeastOneLC = '(?=.*?[a-z])';
atLeastOneUC = '(?=.*?[A-Z])';
atLeastOneDigit = '(?=.*?\d)';
matchAll = '.*';
passwdCriteria = [anchorToStartOfLine,atLeastEightChars,atLeastOneLC,atLeastOneUC,atLeastOneDigit,matchAll];
tf = ~isempty(regexp(str,passwdCriteria,'once'));
  2 comentarios
Andy
Andy el 10 de Abr. de 2014
Thanks for the help! I was able to use what you did for "atleastOneDigit" and turn it into a function to satisfy the assignment. This is actually part of my homework assignment but I couldn't for the life of me figure it out. Thanks again!!
Andrew Newell
Andrew Newell el 10 de Abr. de 2014
Andy, I'm glad to hear that you made your own version for the assignment.

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Más respuestas (1)

Walter Roberson
Walter Roberson el 10 de Abr. de 2014
all(lower(password)==password) implies no capital letters. It does not, however, establish that any lowercase letters were used: the password might contain no alphabetic letters at all.
any(password >= '0' & password <= '9') is one of the ways to check for digits.
You should be considering using regexp() instead of looping.
  2 comentarios
Walter Roberson
Walter Roberson el 10 de Abr. de 2014
Editada: Andrew Newell el 10 de Abr. de 2014
~any(cellfun(@isempty, regexp(str, {'.{8,}', '[A-Z]', '[a-z]', '\d'}, 'match', 'once')))
Andrew Newell
Andrew Newell el 10 de Abr. de 2014
Editada: Andrew Newell el 10 de Abr. de 2014
Nice!

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