Set initial value in Matlab Function block

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William
William el 17 de Abr. de 2014
Respondida: Danilo Teran el 4 de Dic. de 2018
How can I set the initial value for UP? UPI is my initial value input to the block. How can I make sure UP will accepts thhs value only once (start of the simulation)? Thanks
funciton UP=[UPI]
*UP=UPI;
%#close safety_relieve_valve
SRV=0;
if (UP>UL)
Val=0;
UP=RD;
else
Val=1;
UP=RU;
end
if (UP<LL) & (Val==0)
UP=RD+0.1;
disp(UP);
Val=1;
elseif (UP>=LL) & (Val==1)
UP=UP+0.1;
end*
  5 comentarios
Azzi Abdelmalek
Azzi Abdelmalek el 17 de Abr. de 2014
have you tried Ports and Data Manager?
William
William el 17 de Abr. de 2014
The input is set as Inherit: same as Simulink. I kept getting error "Expecting scalr...." I changed the type to "double" but no avail.

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Respuestas (2)

Azzi Abdelmalek
Azzi Abdelmalek el 17 de Abr. de 2014
Editada: Azzi Abdelmalek el 17 de Abr. de 2014
You can use persistent declaration
function UP=fcn(UPI)
persistent UPI1
if isempty(UPI1)
UP=UPI
else
UP=UPI1
end
%your code
UPI1=UP;
  11 comentarios
William
William el 17 de Abr. de 2014
Instead of using the 'elseif' statement, I created another 'if' statement & it worked. But there are some other issues I would like to resolve. I will post it later. Thanks again.
William
William el 19 de Mayo de 2014
Editada: Azzi Abdelmalek el 19 de Mayo de 2014
function UP = UPC(t,LL,u1,u2,u3,u4,u5,u6,u7,u8)
%#codegen
persistent LLI
if isempty(LLI)
UP=LL;
else
UP=LLI;
end
My code
LLI=UP;
Azzi, I kept getting the error message "LLI is not defined..." when I attempted to run the simulation. "LL" is my IC for UP. Any idea? Thanks.

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Danilo Teran
Danilo Teran el 4 de Dic. de 2018
Hi
I have a similar problem, could you find a real solution.
Best regards?

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