How to call a variable with user string input
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Hi all,
I know this is a likely a simple problem, but am having lots of trouble...
I am trying to use an array of data (say 1x50) in a for loop from a user input that is different than the name of the array.
In other words, the user inputs something like 'example' and I need to use the data in the existing array that is named 'exampleD'
exampleD = ones(1,50); % this is an existing array
inp = input('Which dataset are you working with? ','s');
% at this point user enters the string 'example'
Missing code here (some command that will concatenate user input and the letter 'D' to get 'exampleD' which is the name of the existing variable)
for i = 1:50
fprintf(fid,'%f',exampleD(i));
fprintf(fid,',');
end
Any help is greatly appreciated!
2 comentarios
Jorge Ignacio Cisneros Saldana
el 29 de Jul. de 2022
Editada: Jorge Ignacio Cisneros Saldana
el 30 de Jul. de 2022
Do you know how to do same approach without eval command for a parfor loop?.
eval(['dataset = ',variableName,';']);
Walter Roberson
el 30 de Jul. de 2022
If you were able to do an assignment by eval() inside the body of a parfor, there would be no way for matlab to know that the variable had to be returned to the client. If it were possible at all, then it would only be useful for assigning to local variables. And if you are going to be creating local variables you might as well use dynamic field names inside a struct instead of using eval()
Remember that you can assign a struct into a cell array, and then after the parfor merge the struct. Or output a cell of names and a cell of values and then cell2struct after the parfor
Respuesta aceptada
Más respuestas (2)
exampleD = ones(1,50); % this is an existing array
inp = input('Which dataset are you working with? ');
for i = 1:numel(inp)
% whatever
end
1 comentario
Chris
el 13 de Mayo de 2014
Roberto
el 13 de Mayo de 2014
exampleD = ones(1,50); % this is an existing array
inp = input('Which dataset are you working with? ','s');
% at this point user enters the string 'example'
inp = eval([inp 'D']);
for i = 1:50
fprintf(fid,'%f',inp);
fprintf(fid,',');
end
1 comentario
Chris
el 13 de Mayo de 2014
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