Info

La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.

about logical operator in if!

2 visualizaciones (últimos 30 días)
chan
chan el 25 de Mayo de 2014
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
This is my code
y = input('choose','s');
if y == 'a1' | y == '1a'
disp('win')
else
disp('lost')
end
I would like to ask that when I use this, while I am run this program, I type only a or only 1 it also display win, like i type 1a or a1 . explain to me, or me have other ways to write the code, I do not need to add elseif more.
Thanks!

Respuestas (1)

Matt J
Matt J el 25 de Mayo de 2014
Editada: Matt J el 25 de Mayo de 2014
Use strcmp()
if strcmp(y,'a1') || strcmp(y,'1a')
disp('win')
else
disp('lost')
end
As for understanding what's happening currently, observe the result of each of your sub-expressions, and the vectors of logical data they produce, when y='1',
>> y='1';
>> y == 'a1'
ans =
0 1
>> y == '1a'
ans =
1 0
>> y == 'a1' | y == '1a'
ans =
1 1
Since (y == 'a1' | y == '1a') produces a vector of trues, the whole if statement evaluates to true. As mentioned in "doc if",
" An evaluated expression is true when the result is nonemptyand contains all nonzero elements (logical or real numeric). Otherwise,the expression is false. "
  5 comentarios
Matt J
Matt J el 26 de Mayo de 2014
Editada: Matt J el 26 de Mayo de 2014
to see if two things are equal use isequal, ... isequal(y,'a1')
Be careful when using isequal to compare strings. It doesn't check that both arguments are class char, e.g.,
>> isequal(':',58)
ans =
1
whereas,
>> strcmp(':',58)
ans =
0
Matt J
Matt J el 26 de Mayo de 2014
so mean we cannot use the simple condition, right? y == 'a1' | y == 'a1'
You can use these kinds of comparisons when they are appropriate to what you are doing. For example, suppose I want to remove all the spaces in a string,
>> y='This is a short string'; y(y==' ')=''
y =
Thisisashortstring

La pregunta está cerrada.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by