Defining a function (including vector dot product) for all the points in 3D
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
I am trying to build the following function in a three dimensional domain.
where k is a constant vector, X is the position vector, c is a constant number, and t is time.
k is a vector of size [1 3], X is an array of size [NX*NY*NZ 3] that represents the points in the three-dimensional domain, c is a constant, and t is an array of size [1 NT].
The following is the setup of the problem.
dx = 0.1;
dy = 0.5;
dz = 0.1;
[x, y, z] = meshgrid( (1:100)*dx, (1:100)*dy, (1:100)*dz );
X = [x(:) y(:) z(:)];
k = [1 2 3];
c = 0.5;
t = 0:0.1:1;
I thought about using arrayfun and repeating the vector k using repmat and dot it with X in the second dimension but I don't know what I should do for the multiplication of c and t.
In fact, the following loop works but it is very slow (takes 200 seconds on my machine).
f = zeros(numel(X)/3, numel(t));
for n = 1:numel(t)
for i = 1:numel(X)/3
f(i, n) = tan(dot(k, X(i,:)+c*t(n)));
end
end
What would be an efficient way of defining the function for all the points and all the times? The output of this function, for example, looks like an array of size [NX*NY*NZ NT].
1 comentario
Respuesta aceptada
Matt J
el 3 de Jun. de 2014
f = tan( bsxfun(@plus, X*k(:), c*t) );
3 comentarios
Matt J
el 3 de Jun. de 2014
This is probably a bit faster
k = [1 2 3];
c = 0.5;
t = 0:0.1:1;
[x, y, z] = meshgrid( (1:100)*(k(1)*dx),
(1:100)*(k(2)*dy),
(1:100)*(k(3)*dz);
f=tan( bsxfun(@plus, x(:)+y(:)+z(:), ct) );
Más respuestas (1)
George Papazafeiropoulos
el 3 de Jun. de 2014
Editada: George Papazafeiropoulos
el 3 de Jun. de 2014
% data
dx = 0.1;
dy = 0.5;
dz = 0.1;
[x, y, z] = meshgrid( (1:100)*dx, (1:100)*dy, (1:100)*dz );
X = [x(:) y(:) z(:)];
k = [1 2 3];
c = 0.5;
t = 0:0.1:1;
lt=length(t);
% engine
u=numel(X)/3;
t=t(ones(u,1),:);
X=repmat(X,lt,1);
t=t(:);
t=t(:,ones(1,3));
u1=sum(k(ones(numel(X)/3,1),:).*(X+c*t),2);
ff=tan(u1);
% result
ff=reshape(ff,u,[])
0 comentarios
Ver también
Categorías
Más información sobre Matrices and Arrays en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!