How can i put my output numbers in for loop to an array
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Fatih Nurcin
el 17 de Jun. de 2014
Respondida: ubaid haroon
el 1 de Mzo. de 2017
z=('/Users/fatihnurcin/Desktop/Dandnd/dilated')
cd(z)
list = dir('*.bmp');
for i = 1:length(list)
img{i} = imread(list(i).name);
end
for i = 1:length(list)
a=img{i};
b=im2bw(a,0.20);
figure
subplot(1,3,1);
imshow(b)
c=b(120,100:250);
subplot(1,3,3);
plot(c);
for n=1:length(c);
d= padarray(c,[0 1],'replicate','post');
e(n)=d(n)-d(n+1);
left=find(e==1);
right=find(e==-1);
f=right-left;
end
f
end
This is my whole code, it takes a row from a binary photo and tries to find where its black and where its not and calculate the black area so i want to ask how can i put my outputs(outputs are numbers calculated due to black arena) in an array, i couldn't do it by adding (n) to left and right,
left(n)=find(e(n)==1);
right(n)=find(e(n)==-1);
f(n)=right(n)-left(n);
I need an urgent help , i need to deliver my project in 2 days :/
1 comentario
Joseph Cheng
el 17 de Jun. de 2014
reformatted to be readable.
z=('/Users/fatihnurcin/Desktop/Dandnd/dilated')
cd(z)
list = dir('*.bmp');
for i = 1:length(list)
img{i} = imread(list(i).name);
end
for i = 1:length(list)
a=img{i};
b=im2bw(a,0.20);
figure subplot(1,3,1);
imshow(b)
c=b(120,100:250);
subplot(1,3,3);
plot(c);
for n=1:length(c);
d= padarray(c,[0 1],'replicate','post');
e(n)=d(n)-d(n+1);
left=find(e==1);
right=find(e==-1);
f=right-left;
end
f
end
Respuesta aceptada
Jason Nicholson
el 17 de Jun. de 2014
This assumes the bitmaps are all the same size:
myArray = [img{:}];
5 comentarios
Jason Nicholson
el 18 de Jun. de 2014
Honestly, it is clear to me you don't really know what you are doing with MATLAB. After this project is done, you need to read up "getting started" documents for MATLAB. The code below is ugly but works. I believe it is what you want as well.
list = dir('*.bmp');
% preallocate cell array
img = cell(length(list),1);
f = cell(length(list), 250-100);
for i = 1:length(list)
img{i} = imread(list(i).name);
end
for i = 1:length(list)
a=img{i};
b=im2bw(a,0.20);
figure;
subplot(1,3,1);
imshow(b)
c=b(120,100:250);
subplot(1,3,3);
plot(c);
for n=1:length(c);
d= padarray(c,[0 1],'replicate','post');
e(n)=d(n)-d(n+1);
left=find(e==1);
right=find(e==-1);
f{i, n} = right-left;
end
end
Más respuestas (2)
Shravankumar P
el 18 de Jun. de 2014
I guess you may go for index mapping. I just give you Idea try this once
for m=1:4
for n=1:4
X(m,n)=x(4*(m-1)+n);
end
end
x is the input which of your interest to put into an array X
0 comentarios
ubaid haroon
el 1 de Mzo. de 2017
what would you do if during the loop, those arrays are different lengths?
0 comentarios
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