Read file
18 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Hi all,
probably a very simple question..I need to read a text file consisting of a list of vectors with this format:
skip the first 22 line and then (x y z) (x y z) (x y z) ... (x y z)
there are 263853 line. How can i do that??
thanks for any help
andrea
0 comentarios
Respuestas (3)
Jan
el 15 de Feb. de 2011
The description of the file format is not exact enough. I'll show you a method for a well defined format and I assume you can adjust it to your needs:
I assume the file looks like this:
Header line 1
...
Header line 22
(0.1 0.2 0.3)
(0.17 19.5 231)
... <263853 of such lines>
This can be solved by TEXTSCAN or more low-levelish:
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
for iSkip = 1:22
dummy = fgetl(FID);
end
Data = fscanf(FID, '(%g %g %g)\n');
Data = transpose(reshape(Data, 3, []));
fclose(FID);
2 comentarios
Jan
el 15 de Feb. de 2011
Thanking is very polite. Accpeting an answer is helpful for others in addition.
Matt Tearle
el 15 de Feb. de 2011
Or, using textscan (as Jan mentioned):
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
Data = textscan(FID, '(%f %f %f)','headerlines',22);
x = Data{1};
y = Data{2};
z = Data{3};
fclose(FID);
0 comentarios
Ver también
Categorías
Más información sobre Text Data Preparation en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!