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Convert string of hex to array of dec

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John Ramshur
John Ramshur el 17 de Ag. de 2011
I need to convert a string of hexidecimal numbers to an array of dec numbers. The string can potentially contain incomplete hex numbers at the beginning and end of the string. See examples below. I'm trying to use this in a data acquisition setup...so execution time could be a factor.
Input String Examples ('/r' = carriage returns:
s1 = '0001h/r0002h/r0003h/r';
s2 = '4h/r0001h/r0002h/r0003h/r00';
Output Desired:
a1 = [1,2,3]
a2 = [1,2,3]

Respuesta aceptada

Fangjun Jiang
Fangjun Jiang el 17 de Ag. de 2011
s1 = '0001h/r0002h/r0003h/r';
s1 = '4h/r0001h/r0002h/r0003h/r00';
str=regexp(s1,'h/r','split');
Ind=cellfun(@length,str);
str=str(Ind==4);
num=hex2dec(str);
  2 comentarios
John Ramshur
John Ramshur el 17 de Ag. de 2011
Worked perfectly. Thanks.
Jan
Jan el 17 de Ag. de 2011
cellfun('prodofsize', str) is faster than cellfun(@length, str).

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Más respuestas (1)

Jan
Jan el 17 de Ag. de 2011
A simpler method, which is substantially faster:
s1 = '0001h/r0002h/r0003h/r';
a1 = sscanf(a, '%xh/r')
But this does not reject the 4 of the string '4h/r0001h/r0002h/r0003h/r00'!
If you mean \r instead /r:
s1 = sprintf('0001h\r0002h\r0003h\r');
a1 = sscanf(a, '%xh')

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