How can I write a for loop to do algebra over multiple arrays?
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Havi Tripathi
el 20 de Ag. de 2021
Comentada: Havi Tripathi
el 20 de Ag. de 2021
I have 4 1x28 arrays.
I want to solve an equation for time, also linearly spaced as 1x28, for each value in this row.
a = linspace(3,28,28);
b = linspace(4,28,28);
c = linspace(5,28,28);
d = linspace(6,28,28);
time = linspace(1,28,28);
for i = 1:28:
value = a.*time ./ (c+d)
end
So, in the end, value should be a 28x28 array right. The first column of value, for example, should be value evaluated at time 1.
As it goes downward in column 1, it should be evaluated at time 2, etc till 28.
I'm not sure how to actually implement this. When I am doing it regularly, I get back a 1x28 array from value.
Does anyone know the approach or solution I am looking for?
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Respuesta aceptada
Wan Ji
el 20 de Ag. de 2021
Do loop with indices of t:
a = linspace(3,28,28)';
b = linspace(4,28,28)';
c = linspace(5,28,28)';
d = linspace(6,28,28)';
time = linspace(1,28,28);
value = zeros(28,28);
for i = 1:28
value(:,i) = a.*time(i)./ (c+d);
end
And then the value becomes 28*28 as you want.
Más respuestas (1)
Simon Chan
el 20 de Ag. de 2021
Try this:
A = arrayfun(@(x) x.*time./(c+d), a, 'UniformOutput', false)
result = cell2mat(A')
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