How to display the output as table shown below?

z(:,:,1) =
0.4794    0.8776         0
0.0000    1.0000         0
-0.4794    0.8776         0
z(:,:,2) =
0.4794    0.8776    1.0000
0.0000    1.0000    1.0000
-0.4794    0.8776    1.0000
z(:,:,3) =
0.4794    0.8776    2.0000
 0.0000    1.0000    2.0000
-0.4794    0.8776    2.0000

How can I display output as follows?

    z=
Nodenumber(1)           0.4794    0.8776         0
Nodenumber(2)           0.0000    1.0000         0
Nodenumber(3)           -0.4794    0.8776         0
Nodenumber(4)            0.4794    0.8776    1.0000
Nodenumber(5)             0.0000    1.0000    1.0000
Nodenumber(6)           -0.4794    0.8776    1.0000
Nodenumber(7)             0.4794    0.8776    2.0000
Nodenumber(8)              0.0000    1.0000    2.0000
Nodenumber(9)             -0.4794    0.8776    2.0000
 

[per isakson]

Tags in this forum shall not have a leading "#" .

"display output as follows" By typing "z" in the command window you cannot get this output. There will be a lot of brackets.

Answer 1

[Wan Ji]

You can use a table to achieve the output

Node = reshape(permute(z,[1,3,2]),numel(z)/size(z,2), size(z,2));
Nodenumber = char (num2str((1:size(a,1))'));
z = table(Nodenumber,Node)

Answer 2

[Kevin Holly]

z(:,:,1) =[
0.4794    0.8776         0
0.0000    1.0000         0
-0.4794    0.8776         0];

z(:,:,2) =[
0.4794    0.8776    1.0000
0.0000    1.0000    1.0000
-0.4794    0.8776    1.0000];

z(:,:,3) =[
0.4794    0.8776    2.0000
 0.0000    1.0000    2.0000
-0.4794    0.8776    2.0000];

%preallocate
Nodenumber = zeros(size(z,1)*size(z,2),size(z,3));

count =0;
for j = 1:size(z,3)
    for i=1:size(z,1)
        count = count +1;
        Nodenumber(count,:) = z(i,:,j);
    end
end

for ii = 1:size(z,1)*size(z,2)
output{ii} = ['Nodenumber(' num2str(ii) ') ' num2str(Nodenumber(ii,:))];
end

output'

ans = 9×1 cell array
    {'Nodenumber(1) 0.4794      0.8776           0' }
    {'Nodenumber(2) 0  1  0'                        }
    {'Nodenumber(3) -0.4794      0.8776           0'}
    {'Nodenumber(4) 0.4794      0.8776           1' }
    {'Nodenumber(5) 0  1  1'                        }
    {'Nodenumber(6) -0.4794      0.8776           1'}
    {'Nodenumber(7) 0.4794      0.8776           2' }
    {'Nodenumber(8) 0  1  2'                        }
    {'Nodenumber(9) -0.4794      0.8776           2'}

I am unsure what you are looking for, so I created two different outputs.

Nodenumber(1,:)
Nodenumber(2,:)