How to extract certain values from text file to find average of the group of numbers?

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Can you please help me to extract certain column of numbers from a text file. I want to find their average. The following .txt file is as follows. I want only # 25 to 30 sigma values.
Number of unknowns: 1374
Number of observations: 28854 of 28854
Number of constraints: 1246
Number of datum stations: 14
Number of datum sources: 0
vTPv: 67100.6 +/- 1944.94
redundancy: 28726
chi^2: 1.5282 +/- 0.0220971
List of estimated parameters
.----------------------------------------------------------------------------------------------------.
| # | Type | member | reference epoch | sigma [unit] | repeatability [unit] |
|-------|-----------|----------|---------------------|-----------------------|-----------------------|
| 0 | PWL_CLK | AGGO | 2021.05.18 17:00:00 | 0.62888 [cm] | 1.99957 [cm] |
| 1 | PWL_CLK | AGGO | 2021.05.18 18:00:00 | 0.91947 [cm] | 4.93553 [cm] |
| 2 | PWL_CLK | AGGO | 2021.05.18 19:00:00 | 1.64927 [cm] | 8.35032 [cm] |
| 3 | PWL_CLK | AGGO | 2021.05.18 20:00:00 | 2.28501 [cm] | 10.70383 [cm] |
| 4 | PWL_CLK | AGGO | 2021.05.18 21:00:00 | 2.92039 [cm] | 12.11574 [cm] |
| 5 | PWL_CLK | AGGO | 2021.05.18 22:00:00 | 3.51718 [cm] | 12.86139 [cm] |
| 6 | PWL_CLK | AGGO | 2021.05.18 23:00:00 | 4.05227 [cm] | 12.85490 [cm] |
| 7 | PWL_CLK | AGGO | 2021.05.19 00:00:00 | 4.56631 [cm] | 12.34585 [cm] |
| 8 | PWL_CLK | AGGO | 2021.05.19 01:00:00 | 5.02033 [cm] | 11.29844 [cm] |
| 9 | PWL_CLK | AGGO | 2021.05.19 02:00:00 | 5.44759 [cm] | 10.22204 [cm] |
| 10 | PWL_CLK | AGGO | 2021.05.19 03:00:00 | 5.82947 [cm] | 9.16751 [cm] |
| 11 | PWL_CLK | AGGO | 2021.05.19 04:00:00 | 6.17638 [cm] | 8.30392 [cm] |
| 12 | PWL_CLK | AGGO | 2021.05.19 05:00:00 | 6.49624 [cm] | 7.89360 [cm] |
| 13 | PWL_CLK | AGGO | 2021.05.19 06:00:00 | 6.79364 [cm] | 7.92088 [cm] |
| 14 | PWL_CLK | AGGO | 2021.05.19 07:00:00 | 7.06446 [cm] | 8.59745 [cm] |
| 15 | PWL_CLK | AGGO | 2021.05.19 08:00:00 | 7.30998 [cm] | 9.59593 [cm] |
| 16 | PWL_CLK | AGGO | 2021.05.19 09:00:00 | 7.55144 [cm] | 10.44086 [cm] |
| 17 | PWL_CLK | AGGO | 2021.05.19 10:00:00 | 7.77601 [cm] | 11.36565 [cm] |
| 18 | PWL_CLK | AGGO | 2021.05.19 11:00:00 | 8.00764 [cm] | 11.76791 [cm] |
| 19 | PWL_CLK | AGGO | 2021.05.19 12:00:00 | 8.24088 [cm] | 11.82715 [cm] |
| 20 | PWL_CLK | AGGO | 2021.05.19 13:00:00 | 8.49287 [cm] | 11.09234 [cm] |
| 21 | PWL_CLK | AGGO | 2021.05.19 14:00:00 | 8.76043 [cm] | 9.66000 [cm] |
| 22 | PWL_CLK | AGGO | 2021.05.19 15:00:00 | 9.06284 [cm] | 7.28851 [cm] |
| 23 | PWL_CLK | AGGO | 2021.05.19 16:00:00 | 9.41047 [cm] | 4.15836 [cm] |
| 24 | PWL_CLK | AGGO | 2021.05.19 17:00:00 | 9.75290 [cm] | 1.99957 [cm] |
| 25 | PWL_CLK | HART15M | 2021.05.18 17:00:00 | 0.57717 [cm] | 1.75935 [cm] |
| 26 | PWL_CLK | HART15M | 2021.05.18 18:00:00 | 0.88342 [cm] | 4.97802 [cm] |
| 27 | PWL_CLK | HART15M | 2021.05.18 19:00:00 | 1.59244 [cm] | 8.59066 [cm] |
| 28 | PWL_CLK | HART15M | 2021.05.18 20:00:00 | 2.26089 [cm] | 10.78367 [cm] |
| 29 | PWL_CLK | HART15M | 2021.05.18 21:00:00 | 2.90160 [cm] | 12.28015 [cm] |
| 30 | PWL_CLK | HART15M | 2021.05.18 22:00:00 | 3.49047 [cm] | 13.06497 [cm] |
| 31 | PWL_CLK | HART15M | 2021.05.18 23:00:00 | 4.03382 [cm] | 13.11746 [cm] |
| 32 | PWL_CLK | HART15M | 2021.05.19 00:00:00 | 4.54147 [cm] | 12.73883 [cm] |
| 33 | PWL_CLK | HART15M | 2021.05.19 01:00:00 | 5.00205 [cm] | 11.97155 [cm] |
| 34 | PWL_CLK | HART15M | 2021.05.19 02:00:00 | 5.42749 [cm] | 10.89467 [cm] |
| 35 | PWL_CLK | HART15M | 2021.05.19 03:00:00 | 5.81582 [cm] | 9.73427 [cm] |

Respuesta aceptada

Star Strider
Star Strider el 10 de Sept. de 2021
Try this —
T1 = readtable('https://www.mathworks.com/matlabcentral/answers/uploaded_files/734899/Sujata%20Dhar%20%20text%20file%20-%202021%2009%2010.txt', 'VariableNamingRule','preserve');
sigma = regexp(T1{:,6}, '\d*.\d*[^[cm]]','match');
T2 = table(T1{:,2}, str2double([sigma{:}]).', 'VariableNames',{'#','sigma'})
T2 = 36×2 table
# sigma __ _______ 0 0.62888 1 0.91947 2 1.6493 3 2.285 4 2.9204 5 3.5172 6 4.0523 7 4.5663 8 5.0203 9 5.4476 10 5.8295 11 6.1764 12 6.4962 13 6.7936 14 7.0645 15 7.31
sigma_25to30 = T2.sigma(25:30)
sigma_25to30 = 6×1
9.7529 0.5772 0.8834 1.5924 2.2609 2.9016
or possibly —
sigma_25to30 = T2.sigma(T1.('#')>=25 & T2.('#')<=30)
sigma_25to30 = 6×1
0.5772 0.8834 1.5924 2.2609 2.9016 3.4905
I have no idea if this will work with the original text file because it never actually appeared as an uploaded/attached file. If there is a problem with it, use the one supplied here instead, since it works with my code.
Experiment to get different results.
.
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