get the last for digits of the messages and create another array with them

1 visualización (últimos 30 días)
i asked before how to get the last 4 digits of a certain message but what i want to do is to create a string with those numbers here is the code that I hace and an exemple of the type of message:
TimeAIS1 = [];
for i=1:1:N
seq1=AIS1(i)
linia=convertStringsToChars(seq1);
linia(end-3:end)
TimeAIS1 = [TimeAIS1,linia(end-3:end)];
end
TimeAIS1([TimeAIS1],:) = [];
My result is a char and what i want is a string with those numbers. the type of message is the following:
"!AIVDM,2,1,3,B,54hG=R82FP2e`LQc:208E8<v1HuT4LE:2222220U1pI446b;070PDPiC3kPH,0*720000"
Thank you so much

Respuesta aceptada

Cris LaPierre
Cris LaPierre el 14 de Sept. de 2021
They are characters because you convert your string to a character array. Ether convert the result back to a string using string, or better yet, use a function designed to operate on strings like extractAfter.
AIS1(1) = "!AIVDM,2,1,3,B,54hG=R82FP2e`LQc:208E8<v1HuT4LE:2222220U1pI446b;070PDPiC3kPH,0*720000";
TimeAIS1 = [];
for i=1:1
seq1=AIS1(i);
TimeAIS1 = [TimeAIS1,extractAfter(seq1,strlength(seq1)-4)]
end
TimeAIS1 = "0000"
  3 comentarios
Cris LaPierre
Cris LaPierre el 14 de Sept. de 2021
It should be rather easy to run it and see.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Characters and Strings en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by