operations on two different matrices
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I need to replace the first row from a matrix A(m.m) by first row from another matrix B(n.n) with different size?
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the cyclist
el 14 de Sept. de 2021
Editada: the cyclist
el 15 de Sept. de 2021
Suppose ...
m = 3;
n = 4;
A = magic(m)
B = magic(n)
The first row of A is a 1x3 row vector, and the first row of B is a 1x4 row vector. What do you want the output to be? Also, what if m had been greater than n?
6 comentarios
Mohamed Hajjaj
el 15 de Sept. de 2021
the cyclist
el 15 de Sept. de 2021
Sorry, I still don't understand. Let's take a few specific cases. (The vectors represent the first row.) What should the output be in these cases?
Case 1
A = [8 1 6];
B = [16 2 3 13];
newA = [2 3 13]; % This is what you just said, so confident here.
Is the general rule that you take from the right-hand end?
Case 2
A = [16 2 3 13];
B = [8 1 6];
newA = ?; % What should it be?
Case 3
A = [30 39 48 1 10 19 28];
B = [8 1 6];
newA = ?; % What should it be?
Case 4
A = [8 1 6];
B = [30 39 48 1 10 19 28];
newA = ?; % What should it be?
I'm just trying to understand the general rule, and make sure it covers all possible cases.
Mohamed Hajjaj
el 15 de Sept. de 2021
Mohamed Hajjaj
el 15 de Sept. de 2021
the cyclist
el 15 de Sept. de 2021
Sorry, but your last two comments are just confusing to me.
You did not respond to my questions. What are the results for Case 1, Case 2, etc?
I don't know Fortran anymore, so cannot interpret that.
Why are you suddenly introducing new variables (D, DD1, idx)? Your original question seemed very simple, about filling in the first row of a matrix A, from the first row of a matrix B. It seems to be getting more and more complicated with every comment.
Mohamed Hajjaj
el 16 de Sept. de 2021
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