Extracting rows in row-wise manner. How to do this?

Suppose,a matrix A, A=[1 2 3 4; 1 0 2 8; 1 2 3 6....]

Size(A)=100 4

And I want to extract each row in a row-wise manner (ie.row1,then row2, row3....)and then place it in seperate B matrix where 1 row will be used at a time.

How to do this?

[per isakson]

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Answer 1

[KSSV]

Question sounds very silly. You can use a lloop.

A = rand(100,4) ; 
B = zeros(100,4) ; 
for i = 1:100
    thisrow = A(i,:) ; 
    B(i,:) = thisrow ; 
end

Answer 2

[Image Analyst]

Try this:

[rows, columns] = size(A);
for row = 1 : rows
    % Extract a row of A (all columns of it) into a new row vector, B.
    B = A(row, :)
    % Now use B in whatever way you want.  It will get overwritten on each iteration, but that shouldn't matter.
end