In this code I have a result but I want it as integer numbers.

 n = 12;
m = 6;
numbers = linspace(1, n, m)
index = 1;
theSums = [];
for k = 1 : length(numbers)
    for k2 = 1 : length(numbers)
        num1(index) = numbers(k);
        num2(index) = numbers(k2);
        theSums(index) = num1(index) + num2(index);
        fprintf('%.4f + %.4f = %.4f\n', num1(index), num2(index), theSums(index));
        index = index + 1;
    end
end
[uniqueSums, indexes] = unique(theSums)
% Extract only the unique numbers:
num1 = num1(indexes)
num2 = num2(indexes)
% Double check.
for k = 1 : length(indexes)
    fprintf('%.4f + %.4f = %.4f\n', num1(k), num2(k), uniqueSums(k));
end

Answer 1

[Image Analyst]

round() will turn floating point numbers (doubles) with fractions into floating point numbers (doubles) with no fraction (the fraction is 0).

Or you can use int32() to cast your variable into a 32 bit integer, which of course also does the rounding.