polar to cartesian conversion

I have an image displayed which is 742*400 matrix. i need to convert this image into cartesian. for which i need to know the x and y values to be applied in the following formula r= sqrt( (x-x0)^2+(y-y0)^2). now how do i know the x and y values from the matrix?

Answer 1

[Chad Greene]

The x and y values may very well be the dimensions of the matrix, so from 1 to 742 in one direction and 1 to 400 in the other direction. You could make zero the center by subtracting 742/2 in one dimension and 400/2 in the other dimension.

Also, it's hard to know with the information you've given, but this might help: http://www.mathworks.com/matlabcentral/fileexchange/47238-impolar-m

[thirumagal jayaraman]

119 56 34 67

123 45 67 89

120 45 87 90

14 54 32 12

this kind of matrix (742 * 400) i get in workspace from this i need to use x and y values in the above mentioned formula