How can I make imageDatastore sort naturally?

When I use imageDatastore to store files, the files are sorted according to their names like so:
This is how MATLAB sorts them by default. How can I make it store the files in an image datastore in the correct order ('1,5,10,15,20' rather than '1,10,15,20,5')? Or is there a way to create a new datastore with the sorted filenames? I understand that sort_nat or natsortfiles could be used in some way, but I'm not sure how. I can't sort and store the images in any other way(like in a table or directory), it has to be an image datastore.

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Pranay Koppula
Pranay Koppula el 8 de Oct. de 2021
I was able to resolve this finally by doing this:
imds=imageDatastore(filepathofimages);
imds.Files=sort_nat(imds.Files);
Luckily, I only needed to sort the filenames for my project. I don't know how this affects other attributes of the datastore, and to anyone else who might consider trying this solution, I would recommend experimenting with a test datastore to see how this affects other attributes.

2 comentarios

Ameetha
Ameetha el 30 de Ag. de 2022
But Where is sort_nat ? unrecognised function
Kamal
Kamal el 28 de Dic. de 2022
Editada: Kamal el 28 de Dic. de 2022
For some reason i don't know, when you assign the sorted files to imds object which is imds.Files, it removes all the labels that were already assigned by the imagedatastore function which is really important for me later.
Any idea or workaround to avoid losing the labels assigned earlier? @Pranay Koppula @Stephen23

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Más respuestas (1)

yanqi liu
yanqi liu el 8 de Oct. de 2021

3 votos

sir,may be use the 001、002、…… as image filename

3 comentarios

Pranay Koppula
Pranay Koppula el 8 de Oct. de 2021
I think that would lead to the same issue. The problem is that MATLAB reads the numbers as characters and sorts them that way.
Stephen23
Stephen23 el 8 de Oct. de 2021
@Pranay Koppula: actually, if you use sufficient leading zeros then sorting by character does resolve this problem, exactly as yanqi liu writes. This is a robust and very efficient solution.
Pranay Koppula
Pranay Koppula el 9 de Oct. de 2021
You're right, I realised this was true. However, when the total number of frames is not known, we can't know how many leading zeroes we need. In most cases though, it is indeed a robust solution.

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el 8 de Oct. de 2021

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el 28 de Dic. de 2022

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