Creating an array of given size and increment
1.026 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Adam
el 19 de Ag. de 2014
Comentada: Steven Lord
el 27 de Jun. de 2019
This seems like a stupid question from someone with 8 years Matlab experience, but either I'm having a brain fade moment or there is no neat shortcut syntax to this.
I simply want to create an array with a known start, increment and number of elements.
Obviously if I have start, increment, end I can use the colon operator and if I have start, number of elements and end I can use linspace.
But is there really nothing neater than having to do the maths to work out the end point then use one of the above options? I'd rather just let the max be whatever it happens to be.
Calculating an explicit max in order to create a matrix with an implicit increment (using linspace) that should match exactly the increment I used to calculate the max seems very un-Matlab-like.
2 comentarios
Steven Lord
el 27 de Jun. de 2019
A simpler way to count from 0 to 200 in increments of 10 is:
countByTens = 0:10:200;
In the original question, the user knew the starting point (0) and the increment (10) but couldn't use the colon operator because they knew how many fence rails they wanted to use (20 rails) or how many posts they wanted (21) rather than where they wanted their fence to end (200.)
Respuesta aceptada
Rick Rosson
el 19 de Ag. de 2014
How about the following?
xStart = 5;
dx = 0.001;
N = 2000;
x = xStart + (0:N-1)*dx;
Is that what you are looking for?
5 comentarios
Andrew Baker
el 7 de Sept. de 2018
Yes, I was using mod, but obviously in the wrong places, thanks for your help. I think I understand a little more how it's working now aswell.
Andrew
Más respuestas (1)
Ver también
Categorías
Más información sobre Matrix Indexing en Help Center y File Exchange.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!