How does Matlab produce thin edges?
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Ivan Matala
el 21 de Ag. de 2014
Comentada: Royi Avital
el 3 de Sept. de 2019
Im using sobel edge detection.
How does Matlab, by itself manage to achieve very thin edges like this one (using just the Matlab's edge function with 'sobel' as parameter)
matlabsobel = edge(originalImage,'sobel')
imshow(matlabsobel)

but when I try to do sobel algorithm my own way, assuming the process is just the same..
originalImage = gaussianizedimage;
threshold = 60.5;
k = [1 2 1; 0 0 0; -1 -2 -1];
H = conv2(double(originalImage),k, 'same');
V = conv2(double(originalImage),k','same');
E = sqrt(H.*H + V.*V);
edgeImage = uint8((E > threshold) * 255);
imshow(edgeImage);
title('sobel algorithm')

Why is that its different? What is still lacking in my implementation to achieve Matlab's thin edges? Can anyone provide code to make it look/similar to Matlab native sobel edge detection?
Thanks
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Image Analyst
el 21 de Ag. de 2014
edge() takes a grayscale edge image like you'd get with imgradient(), and then thresholds it and skeletonizes the thresholded image, like you'd get with bwmorph(BW, 'Skel', inf).
4 comentarios
Miroslav Hagara
el 19 de Sept. de 2018
Editada: Miroslav Hagara
el 19 de Sept. de 2018
according this, if I use this code:
BW1 = edge(I,'Prewitt');
BW2NT = edge(I,'Prewitt','nothinning');
BW2 = bwmorph(BW2NT, 'Skel',Inf);
I should get the same pictures. But this is not true.
I have get better result with
BW2 = bwmorph(BW2NT, 'thin', Inf)
but still without same pictures.
Royi Avital
el 3 de Sept. de 2019
If you look inside edge() you will see:
if thinning
e = computeedge(b,bx,by,kx,ky,int8(offset),100*eps,cutoff);
else
Which does the magic.
MathWorks doesn't specify what's done there.
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