how to define functions with variable values

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John
John el 21 de Ag. de 2014
Editada: Star Strider el 23 de Ag. de 2014
Hello,
I'm trying to define a function x1=-c1/b1*x2+d1/b1, where b1,c1,d1 are defined, but x2 should be kept as a variable. Here's how it all looks at the end

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Star Strider
Star Strider el 21 de Ag. de 2014
Editada: Star Strider el 21 de Ag. de 2014
You can do that with Anonymous Functions:
x1 = @(x2,b1,c1,d1) -c1./b1.*x2+d1./b1;
if you want to include all the constants as arguments,
or:
x1 = @(x2) -c1./b1.*x2+d1./b1;
if you want to pick the constants up automatically from the workspace.
  2 comentarios
John
John el 23 de Ag. de 2014
Wow! That was quick. It only took you 7 minutes to answer, this other program that I've been using has a way slower community. The anonymous function works great. Though before posting, I tried searching for a similar post and in my findings encountered the anonymous function, without your help I couldn't properly understand how to apply it to my code. Thanks a million!
Star Strider
Star Strider el 23 de Ag. de 2014
Editada: Star Strider el 23 de Ag. de 2014
My pleasure!
There are some truly brilliant people here. (I have my areas of expertise, but nothing to match others like Roger Stafford, Azzi Abdelmalek, Andrei Bobrov, Cedric Wannaz, and others. MATLAB staffers also appear here from time to time to provide detailed Answers the rest of us cannot.) Stay here if you need help. If you ask your Questions clearly, you will get clear Answers.
Also, contribute your own Answers as you gain expertise.
Apologise for the delay this time — GMT-6 here.

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